Ask question

Ask question

All categories

4 years ago

10

Plz help me and explain how you got the answer plz

1 answer:

AfilCa [17]4 years ago

3 0

The decrease was 3. (from 30 down to 27)

Always calculate the decrease as a percent of the ORIGINAL number.

3/30 = 0.1

To change a decimal to a percent, move the point 2 places that way ==> .

0.1 = 10% .

When you go from 30 to 27, that's a decrease of 10% .

You might be interested in

A coffee business sells a pound of coffee for $ 9.75. Monthly expenses are $ 4,500 plus $ 4.25 for every pound of coffee sold. a

hram777 [196]

Answer:

a. IT = 9.75 * X

b. GT = 4500 + 4.25 * X

c. G = 9.75 * X - 4500 - 4.25 * X

Step-by-step explanation:

With the data of the statement we can get a function. Let X be the number of pounds sold.

to. Monthly income

IT = 9.75 * X

b. Monthly expenses

GT = 4500 + 4.25 * X

c. Monthly Earnings (Monthly Income - Monthly Expenses)

G = 9.75 * X - (4500 + 4.25 * X)

G = 9.75 * X - 4500 - 4.25 * X

4 0

3 years ago

Can someone please help me find the value of X?

m_a_m_a [10]

hello

to solve this to solve this

7 0

1 year ago

Charles needed 3/4 cups of rasins. if he has a 1/4 measuring cup, how many times will he need to fi'll it up to get to the right

koban [17]

3 times because if he needs 3/4 cup the. you should use it 3 times. (3/4÷1/4=3)

7 0

3 years ago

Evaluate 4x-6y when x=-3 y=-1

pogonyaev

Answer:

First we substitute

4(-3) - 6(-1)

-7 -6

-13

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Three lines of crops in a garden form a triangular shape. Strawberries are planted in a 10 ft line and green beans are planted i

Marat540 [252]

Answer:

$p = 19.18$

Step-by-step explanation:

This question is illustrated using the attachment and will be solved using cosine formula

$a^2 = b^2 + c^2 - 2bcCosA$

<em>Let the strawberry side be s, the Green beans be b and the pumpkins be p.</em>

<em />

The cosine formula in this case is:

$g^2 = s^2 + p^2 - 2spCosG$

Where

$s = 10$

$g = 18$

The equation becomes

$18^2 = 10^2 + p^2 - 2 * 10 * p * Cos\ 68$

$324 = 100 + p^2 - 20 * p * 0.375$

$324 = 100 + p^2 - 7.5p$

Collect Like Terms

$p^2 - 7.5p + 100 - 324 = 0$

$p^2 - 7.5p - 224 = 0$

Using quadratic formula:

$p = \frac{-b\±\sqrt{b^2-4ac}}{2a}$

Where

$a = 1$

$b = -7.5$

$c = -224$

$p = \frac{-(-7.5)\±\sqrt{(-7.5)^2-4*1*-224}}{2*1}$

$p = \frac{7.5\±\sqrt{56.25+896}}{2}$

$p = \frac{7.5\±\sqrt{952.25}}{2}$

$p = \frac{7.5\± 30.86}{2}$

$p = \frac{7.5 + 30.86}{2}$ or $p = \frac{7.5 - 30.86}{2}$

$p = \frac{38.36}{2}$ or $p = \frac{-23.36}{2}$

$p = 19.18$ or $p = -11.68$

But length can not be negative.

So:

$p = 19.18$

6 0

3 years ago