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nordsb [41]
3 years ago
9

According to the general equation for conditional probability, if P(AuB')=5/9 and P(B)=1/3, what is P(A|B')?

Mathematics
1 answer:
aev [14]3 years ago
3 0
P(B)=\frac{1}{3}
P(B')=1-\frac{1}{3}=\frac{2}{3}
P(A|B')=\frac{P(A\cap B')}{P(B')}=\frac{\frac{5}{9}}{\frac{2}{3}}=\frac{5}{6}
The correct answer choice is C.
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Answer:

The probability is: 0.8889.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Approved

Event B: Qualified

Probability of a person being approved:

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30% of 25%(not qualified). So

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P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.8*0.75}{0.675} = 0.8889

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The French club is holding a car wash fundraiser. They are going to charge $10 per car, and expect between 50 and 75 cars. Ident
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It is given in the question that,

The French club is holding a car wash fundraiser. They are going to charge $10 per car, and expect between 50 and 75 cars.

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