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3 years ago

5(-12x+3)+6(10x+7)=9-x+3x+10

Mathematics

1 answer:

tia_tia [17]3 years ago

8 0

Answer: x = 19

Step-by-step explanation:

5(-12x+3) + 6(10x + 7) = 9 - x + 3x + 10 Distribute on the left side

-60x + 15 + 60x + 42 = 9 + 2x + 10 combine like terms on the left side

57 = 9 + 2x + 10 Now combine like terms on the right side

57 = 2x + 19 Subtract 19 from both sides

-19 -19

38 = 2x Divide both sides by 2

x = 19

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3 years ago

Solve for x and y. 4x-3y=16 -2x+4y=-2 DUE 2/7/17!

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$\left \{ {{4x-3y=16\:(I)} \atop {-2x+4y=-2\:(II)}} \right.$

Multiply the 2nd equation by (-4). This will eliminate the x's when you add the two new equations together.
 $\left \{ {{4x-3y=16\:\:\:\:\:\:\:\:\:\:} \atop {-2x+4y=-2\:*(-4)}} \right.$
$\left \{ {{\diagup\!\!\!\!4x-3y=16} \atop {-\diagup\!\!\!\!4x+8y=-4}} \right.$
--------------------
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$\boxed{\boxed{y = \frac{12}{5}}}\end{array}}\qquad\quad\checkmark$

Let's replace the value found in the first equation:
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$\frac{20x}{\diagup\!\!\!\!5} - \frac{36}{\diagup\!\!\!\!5} = \frac{80}{\diagup\!\!\!\!5}$
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3 years ago

HELP ASAP:

tekilochka [14]

Answer:

Here's how I would do it.

Step-by-step explanation:

If two triangles are similar, corresponding sides are in the same ratio.

We know the measures of b and a, so we can calculate the ratio b/a.

d and b are in the same ratio, so

$\begin{array}{rcl}\dfrac{d}{c}& = & \dfrac{b}{a}\\d & = & c \times \dfrac{b}{a}\\\end{array}$

We know the measures of c, b, and a, so we can calculate the value of d.

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3 years ago

5(-12x+3)+6(10x+7)=9-x+3x+10​

5(-12x+3)+6(10x+7)=9-x+3x+10