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Fynjy0 [20]
3 years ago
14

The area of a rectangle is 10 cm^2. One side of the rectangle is x cm. Express the perimeter of the rectangle in terms of x and

show that this rectangle cannot have a perimeter of 12 cm.
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Area of rectangle = 10cm²

We know that, Area of rectangle = lb

lb = 10

Let l = x cm. Then b = 10/x cm.

Perimeter of rectangle

= 2(l + b) \\  = 2(x +  \frac{10}{x}) \\  =  \frac{2 {x}^{2} + 10 }{x}cm.

But, this rectangle can't have 12 as its perimeter because Sides have to be factors of 10.If l = 5cm and b = 2cm then it will have perimeter 14cm.If l = 10cm and b = 1cm then it will have perimeter 22cm.

Hope this will help you. 

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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
Find the place value of 8 in 2456.1387.<br> Tenths<br> Hundredths<br> Thousandths<br> Thousands
rjkz [21]

Answer: Third Choice. Thousandths

Step-by-step explanation:

<u>Concept:</u>

Here, we need to know the order and name of each place value.

Please refer to the attachment below for the specified names.

<u>Solve:</u>

<em>STEP ONE: Orde and name each place</em>

2 ⇒ One Thousands

4 ⇒ Hundreds

5 ⇒ Tens

6 ⇒ Ones

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1 ⇒ Tenths

3 ⇒ Hundredths

8 ⇒ One Thousandths

7 ⇒ Ten Thousandths

<em>STEP TWO: Find the number [8] in the number</em>

As we can see from the list above, 8 is at the right of the decimal point, thus, the place value is <u>Thousandths</u>.

Hope this helps!! :)

Please let me know if you have any questions

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