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Fynjy0 [20]
3 years ago
14

The area of a rectangle is 10 cm^2. One side of the rectangle is x cm. Express the perimeter of the rectangle in terms of x and

show that this rectangle cannot have a perimeter of 12 cm.
Mathematics
1 answer:
frosja888 [35]3 years ago
7 0

Area of rectangle = 10cm²

We know that, Area of rectangle = lb

lb = 10

Let l = x cm. Then b = 10/x cm.

Perimeter of rectangle

= 2(l + b) \\  = 2(x +  \frac{10}{x}) \\  =  \frac{2 {x}^{2} + 10 }{x}cm.

But, this rectangle can't have 12 as its perimeter because Sides have to be factors of 10.If l = 5cm and b = 2cm then it will have perimeter 14cm.If l = 10cm and b = 1cm then it will have perimeter 22cm.

Hope this will help you. 

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X = 5/3 and m∠SPY = 8 1/3°.

Since PQ bisects the angle, the two angles formed by the bisector are equal:

11/2x - 5 = 4x - 5/2

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Subtract 8x from each side:
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Add 10 to both sides:
3x - 10 + 10 = -5 + 10
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3x/3 = 5/3
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Now we will plug this in for x in both smaller angles and add them together to find the measure of ∠SPY:

11/2(5/3) - 5 + 4(5/3) - 5/2
55/6 - 5 + 20/3 - 5/2

We will rewrite everything using a denominator of 6:
55/6 - 30/6 + 40/6 - 15/6 = (55-30+40-15)/6 = 50/6 = 8 2/6 = 8 1/3°
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