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2 years ago

10

7x^2 - 16x - 15please help find the factored form

1 answer:

myrzilka [38]2 years ago

8 0

Step-by-step explanation:

7x^×2-16x-15

14x^-16x-15

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Please help me with this question!

Dvinal [7]

Answer:

The two-liter bottle of soda has a unit price of $0.028/ounce.

The case of twelve 12 ounces has a unit price of $0.021/ounce.

The case of twelve 12 ounce can is the better bargain.

Step-by-step explanation:

A two-liter bottle of soda i.e. 67.6 ounces cost $1.89.

So, the unit price (price/ounces) of this type of soda is $\frac{1.89}{67.6} = 0.028$ dollars per ounce.

Again, a case of twelve 12 ounce cans of the same soda costs $2.99.

So, the unit price (price/ounces) of this type of soda is $\frac{2.99}{12 \times 12} = 0.021$ dollars per ounce.

Therefore, the case of twelve 12 ounce can is the better bargain. (Answer)

3 0

3 years ago

Which of the following accurately compare 15-√105 and 5?

IceJOKER [234]

Answer:

What are the following?

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Is x a solution to 80<-9x+8

saveliy_v [14]

Answers: $x$

1. Switch sides

$-9x+8>80$

2. Subtract by 8 from both sides of equation.

$-9x+8-8>80-8$

3. Simplify.

$-9x>72$

4. Multiply by -1 from both sides of equation. (it's should be the reverse inequality).

$(-9x)(-1)$

5. Simplify.

$9x$

6. Then you had to divide by 9 from both sides of equation.

$\frac{9x}{9}< \frac{-72}{9}$

7. Simplify.

$\frac{9x}{9}=x$

8. Divide by the numbers.

$\frac{9}{9}=1$

$=x$

$\frac{-72}{9}=-8$

9. Divide by the numbers.

$\frac{72}{9}=8$

$=-8$

$x$

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3 0

3 years ago

Prove that√P is irrational for any prime number P

Luda [366]

Answer:

Step-by-step explanation:

I’m not sure if this is super accurate, but since P is prime, the only factors it has is 1 and itself, meaning that the square root of it will be irrational

3 0

3 years ago

A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t

11Alexandr11 [23.1K]

Answer:

<u>Question 1:</u> $dm/dt=0.2m$ <u />

<u />

<u>Question 2:</u> $m=Ae^{(0.2t)}$ <u />

<u />

<u>Question 3:</u> $m=10e^{(0.2t)}$ <u />

<u />

<u>Question 4:</u> $m=10g$ <u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition: $m'=dm/dt$

b) Given: $rate=0.2m$

c) By substitution: $dm/dt=0.2m$

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

$dm/m=0.2dt$

b)<u> Integrate</u>

$\int dm/m=\int 0.2dt$

$ln(m)=0.2t+C$

c) <u>Antilogarithm</u>

$m=e^{0.2t+C}$

$m=e^{0.2t}\cdot e^C$

$e^C=A\\\\m=Ae^{(0.2t)}$

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

$t=3hours,dm/dt=4g/h$

First, find the mass at t = 3 hours

$dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g$

Now substitute in the general solution of the differential equation, to find A:

$m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976$

Round A to 1 significant figure:

A = 10.

<u>Particular solution:</u>

$m=10e^{(0.2t)}$

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

$m=10e^{0}\\\\m=10g$

3 0

3 years ago