Slope formula:
m = y2 - y1 / x2 - x1
Line QR: (2,8) (3,10)
m = 10 - 8 / 3 - 2 = 2 / 1 = 2
Line ST: (0,6) (-2,2)
m = 2 - 6 / -2 - 0 = -4/-2 = 2
<span>c. parallel because the slopes are the same</span>
3/19 = 0.157...not this one
3/16 = 0.1875...not this one
3/11 = 0.2727 <== this one does
3/8 = 0.375...not this one
Answer:
Step-by-step explanation:
1). m∠AEC = m∠AEB + m∠BEC
= 21° + 37°
= 58°
2). m∠BED = m∠BEC + m∠CED
= 37° + 44°
= 81°
3). m∠IKF = m∠IKH + m∠HKG + m∠GKF
= m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]
= 2∠IKH + m∠HKG
103° = 2∠IKH + 41°
2(∠IKH) = 103 - 41
m(∠IKH) = 31°
4). m∠AED = m∠AEB + m∠BEC + m∠CED
= 21° + 37° + 44°
= 102°
5). m∠JKG = 108°
m∠JKG = m∠JKI + m∠IKH + m∠HKG
108° = m∠JKI + 31° + 41°
m∠JKI = 108° - 72°
m∠JKI = 36°
6). m∠HKF = m∠GKF + m∠HKG
= m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]
= 31° + 41°
= 72°
7). m∠NQO = m∠MQN = 64°
8). m∠JKF = m∠JKI + m∠IKF
= 36° + 103°
= 139°
8). m∠MQO = 2(m∠NQO)
= 2(64)°
= 128°
9). m∠LQO = 156°
m∠LQM = m∠LQO - m∠MQO
= 156° - 128°
= 28°
10. m∠NQP = m∠NQO + m∠OQP
= 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]
= 64° + 28°
= 92°
you need to get a common denominator and subtract 20/32 from 26/32
z would equal 6
Answer:
2nd option
Step-by-step explanation:
r + 1 = 23 ( subtract 1 from both sides )
r = 22 ( multiply both sides by 3 to clear the fraction )
r = 66 ( divide both sides by )
r = 
× 
( rationalising the denominator )
r = 
= 33
