7.380 times 10 to the 9th power (or 7.38 times 10 to the 9th power)
Hello!
So, this is quite the complex question, and here are the following steps:
What is the quotient of ![\frac{6-3\sqrt[3]{6}}{\sqrt[3]{9}}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6-3%5Csqrt%5B3%5D%7B6%7D%7D%7B%5Csqrt%5B3%5D%7B9%7D%7D%20%20)
?
![\frac{(6 - 3\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%286%20-%203%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B9%7D%20%20%20%20%20)
(rationalize the denominator)
![\frac{3(2 -\sqrt[3]{6})\sqrt[3]{9^{2}}}{9}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%282%20-%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B9%7D%20%20%20%20%20)
(factor 3 from the expression)
![\frac{(2-\sqrt[3]{6})\sqrt[3]{9^{2}}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B%282-%5Csqrt%5B3%5D%7B6%7D%29%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B3%7D%20%20%20%20%20)
(reduce the fraction with 3)
![\frac{2\sqrt[3]{9^{2}}-\sqrt[3]{9^{2}}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D-%5Csqrt%5B3%5D%7B9%5E%7B2%7D%7D%7D%7B3%7D%20%20%20%20%20%20%20%20)
(distributive property)
![\frac{2\sqrt[3]{81}-\sqrt[3]{486}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B2%5Csqrt%5B3%5D%7B81%7D-%5Csqrt%5B3%5D%7B486%7D%7D%7B3%7D%20)
(simplify 3 · 9²)
![\frac{6\sqrt[3]{3}-3\sqrt[3]{18}}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B6%5Csqrt%5B3%5D%7B3%7D-3%5Csqrt%5B3%5D%7B18%7D%7D%7B3%7D%20%20%20%20)
(simplify the radical)
![\frac{3(2\sqrt[3]{3}-3\sqrt[3]{18})}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%282%5Csqrt%5B3%5D%7B3%7D-3%5Csqrt%5B3%5D%7B18%7D%29%7D%7B3%7D%20%20%20%20)
(factor 3 from the expression)
![2\sqrt[3]{3}-\sqrt[3]{18}](https://tex.z-dn.net/?f=%202%5Csqrt%5B3%5D%7B3%7D-%5Csqrt%5B3%5D%7B18%7D%20%20%20%20)
(reduce the fraction)
The answer, is simply, choice A, ![2\sqrt[3]{3} -\sqrt[3]{18}](https://tex.z-dn.net/?f=%202%5Csqrt%5B3%5D%7B3%7D%20-%5Csqrt%5B3%5D%7B18%7D%20%20)
≈ 0.263758.
N=1 4+7n=71 that is the answer
Answer: 65.94
Step-by-step explanation:
Find the area of the middle circle.
3.14 x 2² = 12.56
Pretend the white area doesn't exist and find the area of the shaded region.
3.14 x 5² = 78.5
Then subtract.
78.5 - 12.56 = 65.94
Answer:
j(x) = [ (3/10) cookie/student ]x
Step-by-step explanation:
The "unit rate" here is
3 jumbo cookies
------------------------- = (3/10) cookie/student
10 students
Then the number of cookies needed to feed x students is
j(x) = [ (3/10) cookie/student ]x
