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Makovka662 [10]
3 years ago
10

Can someone help me!!!!

Mathematics
2 answers:
Sladkaya [172]3 years ago
8 0

 

\displaystyle\\m(\sphericalangle JKM)=\frac{1}{2}m(\sphericalangle JKL)\\\\ \text{Correct answer is A}




raketka [301]3 years ago
6 0

Answer:

Question 54a: Option A

Question 54b: Bisect <JKM

Question 54c: First, bisect the 60 degree angle to create a 30 degree angle. Next you bisect the 30 degree angle to create 15 degree angle.

Step-by-step explanation:

Question 54a: ray KM, is a bisector of <JKL, thus m<JKM is 1/2 of <JKL

Question 54b: Bisecting a angle the is half of another angle would create an angle that is one fourth of the overall angle.

Question 54c: Bisecting angles cuts them in half.

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f(x) = -4x^2+12x-9f(x)=−4x 2 +12x−9f, left parenthesis, x, right parenthesis, equals, minus, 4, x, squared, plus, 12, x, minus,
Olin [163]

Answer:

The graph has only one x-intercept

Step-by-step explanation:

we have

f(x)=-4x^2+12x-9

we know that

The discriminant of a quadratic equation of the form

ax^{2} +bx+c=0

is equal to

D=b^{2}-4ac

in this problem we have

f(x)=-4x^2+12x-9

so

a=-4\\b=12\\c=-9

substitute

D=12^{2}-4(-4)(-9)

D=144-144

D=0

The discriminant is zero

That means ----> The quadratic equation has one real solution

The graph has only one x-intercept

3 0
3 years ago
A professor at a local university noted that the exam grades of her students were normally distributed with a mean of 73 and a s
Umnica [9.8K]

Answer:

88.51 is the minimum score needed to receive a grade of A.          

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 73

Standard Deviation, σ = 11

We are given that the distribution of exam grades is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

We have to find the value of x such that the probability is 0.0793.

P( X \geq x) = P( z \geq \displaystyle\frac{x - 73}{11})=0.0793  

= 1 -P( z \leq \displaystyle\frac{x - 73}{11})=0.0793  

=P( z \leq \displaystyle\frac{x - 73}{11})=0.9207  

Calculation the value from standard normal z table, we have,  

P(z \leq 1.410) = 0.9207

\displaystyle\frac{x - 73}{11} = 1.410\\x =88.51  

Hence, 88.51 is the minimum score needed to receive a grade of A.

3 0
3 years ago
HELP PLZ ANYONE??? I AM VERY STUCK ASAP!!
Katena32 [7]

Answer:

The answer is A

Step-by-step explanation:

When you multiple the numerators across you get 39,283.2 not 39, 832. What this math problem is, is Dimensional Analysis. Its converting one unit of measurement to another

Another example:

Look at the attachment below.

3 0
3 years ago
Pls I need help fast and quick it's urgent!
sammy [17]

Answer:

I might be wrong but I think its the last answer choice.

Step-by-step explanation:

I'm sorry if its wrong :(

6 0
3 years ago
if i have a line y=4x+7. I want to create another line that is perpendicular through point A (16,2). What is the new equation?
Charra [1.4K]
Perpendicular lines have the negative reciprocal slope, so the slope of your new line will be -1/4 and the current equation will be as follows:
y = -1/4x + b
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to find b, plug in point A and you'll get:
2 = -1/4(16) + b
2 = -4 + b
6 = b

the equation will be:
y = -1/4x + 6
4 0
3 years ago
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