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Bad White [126]
3 years ago
9

​​ How can you find the volume of a rectangular prism with the following dimensions: length = 7, width = 5, height = 11?

Mathematics
2 answers:
scoundrel [369]3 years ago
5 0

Answer:

It's D

Step-by-step explanation:

Answer is 385

Makovka662 [10]3 years ago
3 0
It is going to be D because the formula for volume is length•width•height
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Simplify the rational expression. State any restrictions on the variable. t^2-4t-32/t-8
Leno4ka [110]

1. Factor the expression t^2-4t-32:

t^2-4t-32=(t-8)(t+4).

2. Since t-8 is placed in the denominator of the given expression, then t\neq 8.

3. Now the expression can be simplified:

\dfrac{t^2-4t-32}{t-8}=\dfrac{(t-8)(t+4)}{t-8}=t+4.

5 0
4 years ago
Read 2 more answers
What is the value of Z in the equation to Z +7 equals -5
tangare [24]

Answer:

-12

Step-by-step explanation:

The Equation:

z + 7 = -5

Solve for the variable, z by isolating it. Note the equal sign, what you do to one side, you do to the other.

Note the rule PEMDAS.

PEMDAS is the order of operation & =

Parenthesis

Exponents (& roots)

Multiplication

Division

Addition

Subtraction

Isolate the variable. To do so, subtract 7 from both sides:

z + 7 = -5

z + 7 (-7) = -5 (-7)

z = -5 - 7

Simplify:

z = -5 - 7

z = -12

-12 is your value for z.

~

6 0
3 years ago
Read 2 more answers
Hay there can anybody answer this
Alexus [3.1K]

Answer:

  x = 12

Step-by-step explanation:

The two marked angles where the transversal crosses the parallel lines are alternate interior angles, so are congruent. This fact gives you the relation you need to solve for x.

  4x +12 = 60

  4x = 48 . . . . . . subtract 12

  x = 12 . . . . . divide by 4

5 0
2 years ago
Question -
Sauron [17]

\rule{200}4

Answer : <em>The</em><em> </em><em>required</em><em> </em><em>ratio</em><em> </em><em>is</em><em> </em><em>(</em><em>1</em><em>4</em><em>m</em><em>-</em><em>6</em><em>)</em><em>:</em><em>(</em><em>8</em><em>m</em><em>+</em><em>2</em><em>3</em><em>)</em><em> </em><em>.</em>

\rule{200}4

Here we are given that the ratio of sum of first n terms of two AP's is (7n + 1):(4n + 27) .

That is.

\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{7n +1}{4n +27}  \\

As , we know that the sum of n terms of an AP is given by ,

\small\sf\longrightarrow \pink{ S_n =\dfrac{n}{2}[2a +(n-1)d]} \\

Assume that ,

  • First term of 1st AP = a
  • First term of 2nd AP = a'
  • Common difference of 1st AP = d
  • Common difference of 2nd AP = d'

Using this we have ,

\small\sf\longrightarrow \dfrac{S_1}{S_2}=\dfrac{\dfrac{n}{2}[2a + (n-1)d]}{\dfrac{n}{2}[2a' +(n-1)d'] } \\

\small\sf\longrightarrow \dfrac{7n+1}{4n+27}=\dfrac{2a + (n -1)d}{2a' + (n -1)d' } . . . . . (i) \\

Now also we know that the nth term of an AP is given by ,

\longrightarrow\sf\small \pink{ T_n = a + (n-1)d}\\

Therefore,

\longrightarrow\sf\small \dfrac{T_{m_1}}{T_{m_2}}= \dfrac{ a + (n-1)d }{a'+(n-1)d'}. . . . . (ii)\\

\longrightarrow\sf\small \dfrac{T_1}{T_2}=\dfrac{2a + (2n-2)d}{2a'+(2n-2)d'} . . . . . (iii)\\

From equation (i) and (iii) ,

\longrightarrow\sf\small n-1 = 2m-2\\

\longrightarrow\sf\small n = 2m -2+1 \\

\longrightarrow\sf\small n = 2m -1 \\

Substitute this value in equation (i) ,

\longrightarrow \sf\small \dfrac{2a+ (2m-1-1)d}{2a' +(2m-1-1)d'}=\dfrac{7(2m-1)+1}{4(2m-1) +27}\\

Simplify,

\longrightarrow\sf\small \dfrac{ 2a + (2m-2)d}{2a' +(2m-2)d'}=\dfrac{14m-7+1}{8m-4+27}\\

\longrightarrow\sf\small \dfrac{2[a + (m-1)d]}{2[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\

\longrightarrow\sf\small \dfrac{[a + (m-1)d]}{[a' + (m-1)d']}=\dfrac{ 14m-6}{8m+23}\\

From equation (ii) ,

\longrightarrow\sf\small \underline{\underline{\blue{ \dfrac{T_{m_1}}{T_{m_2}}=\dfrac{ 14m-6}{8m+23}}}}\\

\rule{200}4

8 0
2 years ago
Find the measure of the indicated angle to the nearest degree.
azamat

Step-by-step explanation:

Let the measure of required angle be x degree

\therefore \tan \: x =  \frac{45}{28}  \\  \\ \therefore \tan \: x =  1.60714286  \\  \\ \therefore  \: x =   {\tan}^{ - 1} (1.60714286)  \\  \\  \therefore  \: x =   {\tan}^{ - 1} ( \tan \: 58.109 \degree) \\  \\    \huge \red{ \boxed{\therefore  \: x =   58\degree}}

Thus, first option is the correct answer.

6 0
3 years ago
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