All categories

2 years ago

Solve for Z! If you can explain

Mathematics

1 answer:

Bogdan [553]2 years ago

7 0

The answer is Z=-3 :)

You might be interested in

A password is required to be 12 to 16 characters in length. Characters can be digits (0-9), upper or lower-case letters (A-Z, a-

valkas [14]

Answer:

Step-by-step explanation:

You can find your answer in attached document.

4 0

3 years ago

A triangle is 6 centimeters long and 4 centimeters high. What is the area of the triangle?

schepotkina [342]

24cm
You multiply 6*4=24. Hope this helps! Also can u mark brainliest i need one more :)

6 0

3 years ago

PLEASE HELP ASAP

Ahat [919]

Answer:

5x+32

Step-by-step explanation:

So write out as an expression

Amy= x

Baz = x+8

Carla = 3(x+8)

Total= x +x + 8 +3x+ 24

= 5x+32

8 0

3 years ago

If 4 to the 3 power • 4 to the 3 power = m to the 6 power then m is

Sedbober [7]

4.
4^3 = 64
64X64 = 4096
4^6 = 4096

5 0

3 years ago

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

2 years ago