Answer:
It emits energy since to move from a higher energy level to a lower energy level or ground state, it must lose energy.
Answer:
a) HCN - hybridization sp
b) C(CH₃)₄ - hybridization sp³
c) H₃O⁺ - hybridization sp³
d) - CH₃ - hybridization sp³
Explanation:
Hybridization occurs to allow an atom to make more covalent bonds than the original electronic distribution would allow or to allocate ligands in an energetically stable geometry.
Carbon can have thre hybridization states: sp³ , sp² and sp.
Oxygen usualluy has an sp³ hybridization.
In order to determine the hybridization, we need to consider the number of atoms attached to the central atom and the number of lone pairs.
The figure attached shows the species and the hybridization of their central atoms.
Answer:
Moles of air 0.1245 mol.
Explanation:
Given data:
Pressure = 1 atm
Temperature = 293 K
Volume = 3 L
Number of moles = ?
Solution:
PV = nRT
R = general gas constant = 0.0821 dm³ atm . K⁻¹ . mol⁻¹
Now we will put the values in equation
PV = nRT
n = PV / RT
n = 1 atm . 3 L / 0.0821 dm³ atm . K⁻¹ . mol⁻¹ . 293 K
n = 3 / 24.1 dm³ atm. mol⁻¹
n = 0.1245 mol