The average rate of formation of O2 is 4.225 × 10-4 M min-1
<h3>What is the equation of the reaction?</h3>
The equation of the reaction is given below:
From the equation of the reaction, 2 moles of Ibuprofen pentoxide decomposes to produce 1 mole of oxygen.
<h3>What is the average rate of formation of 02?</h3>
Rate of reaction is given as:
- Moles of product formed/moles of reactants used up/ time
- The ratio of mole of dinitrogen pentoxide decomposed to moles of oxygen produced is 2:1
Rate of disappearance of N2O5 = 8.45×10-4 M min-1.
Therefore, average rate of formation of O2 = 1/2 × 8.45×10-4 M min-1
Average rate of formation of O2 = 4.225 × 10-4 M min-1
Therefore, the average rate of formation of O2 is 4.225 × 10-4 M min-1
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The Ancient Egyptians used simple sundials and divided days into smaller parts, and it has been suggested that as early as 1,500BC, they divided the interval between sunrise and sunset into 12 parts. ... Known as a clepsydra, it uses a flow of water to measure time.
B. At the equivalence point of a titration of the [H+] concentration is equal to 7.
<h3>What is equivalence point of a titration?</h3>
The equivalence point of a titration is a point in titration at which the amount of titrant added is just enough to completely neutralize the analyte solution.
At the equivalence point in an acid-base titration, moles of base equals moles of acid and the solution only contains salt and water.
At the equivalence point, equal amounts of H+ and OH- ions combines as shown below;
H⁺ + OH⁻ → H₂O
The pH of resulting solution is 7.0 (neutral).
Thus, the pH at the equivalence point for this titration will always be 7.0.
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