Answer:
Resonance hybrid: A weighted average of all significant resonance contributors depicting the true electronic structure of a molecule.
Explanation:
Translation: Híbrido de ressonância: uma média ponderada de todos os contribuintes de ressonância significativos, representando a verdadeira estrutura eletrônica de uma molécula.
= 6.022 × 1020
Explanation<em>;</em>
Mole of aluminium oxide (Al2O3) is
⇒ 2 x 27 + 3 x 16
Mole of aluminium oxide = 102 g
i.e., 102 g of Al2O3= 6.022 x 1023 molecules of Al2O3
Then, 0.051 g of Al2O3 contains = 6.022 x 1023 / (102 x 0.051 molecules)
= 3.011 x 1020 molecules of Al2O3
The number of aluminium ions (Al3+) present in one molecule of aluminium oxide is 2.
Therefore, the number of aluminium ions (Al3+) present in 3.11 × 1020 molecules (0.051g) of aluminium oxide (Al2O3)
= 2 × 3.011 × 1020
=<em> 6.022 × 1020</em>
<em>hope </em><em>it </em><em>helps</em><em>_</em>
Answer:
374°F
463.15K
Explanation:
This particular Question wants to test knowledge on the conversion of the units of temperature from celsius degree to degree Fahrenheit. Also, the conversion of degree celsius to kelvin.
The value given which is 190 degree celsius can be converted into degree Fahrenheit using the formula below;
(x°C × 9/5 ) + 32.
Therefore, x = 190°C =( 190°°C × 9/5) + 32 = 374°F.
The conversion of degree celsius to kelvin is given below as;
x°C + 273.15 .
Therefore, x = 190°C = 190°C + 273.15 = 463.15K.
Therefore, the temperature needed to bake at Fahrenheit and kelvin are 374°F and 463.15K respectively.
Except for the Middle East :)
Answer:
4.90 moles of 
will produce (9.8) moles of 
,
(4.90) moles of 
and
(39.2) moles of 
Explanation:
From the question we are told that
The number of moles of is 
The formation reaction of is
From the reaction we see that
1 mole of is formed by 2 moles of 1 mole of and 4
This implies that
4.90 moles of will produce (2 * 4.90) moles of ,
(1 * 4.90) moles of and
(8 * 4.90) moles of
So
4.90 moles of will produce (9.8) moles of ,
(4.90) moles of and
(39.2) moles of
