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Readme [11.4K]
3 years ago
15

Determine the hybridization around the central atom for each of the following molecules.

Chemistry
1 answer:
alina1380 [7]3 years ago
3 0

Answer:

a) HCN  - hybridization sp

b) C(CH₃)₄ - hybridization sp³

c) H₃O⁺  - hybridization sp³

d) - CH₃ - hybridization sp³

Explanation:

Hybridization occurs to allow an atom to make more covalent bonds than the original electronic distribution would allow or to allocate ligands in an energetically stable geometry.

Carbon can have thre hybridization states: sp³ , sp² and sp.

Oxygen usualluy has an sp³ hybridization.

In order to determine the hybridization, we need to consider the number of atoms attached to the central atom and the number of lone pairs.

The figure attached shows the species and the hybridization of their central atoms.

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Barium reacts with a polyatomic ion to form a compound with the general formula Ba3(X)2. What would be the most likely formula f
AfilCa [17]

Answer:

D. Na₃X

Explanation:

We have the neutral compound Ba₃(X)₂. <em>The total charge (zero) is equal to the sum of the charges of the ions times the number of ions in the molecule</em>.

3 × qBa + 2 × qX = 0

3 × (+2) + 2 × qX = 0

2 × qX = -6

qX = -3

If we have the cation Na⁺ and X³⁻, a neutral molecule would require 3 Na⁺ and 1 X³⁻. The resulting compound is Na₃X.

3 0
3 years ago
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The unit "troy ounce" is often used for precious metals such as gold (Au) and platinum (Pt) (1 troy ounce= 31.103 g). (a) A gold
frez [133]

Answer:

Explanation:

a) 1 troy ounce is equal to 31.103 g

2.41 troy ounce is equal to 2.41 x 31.103 g

= 74.958 g

b) 1  ounce = 1 / 16 lb = 1/16 x 453.6 g = 28.35 g.

1 troy ounce = 31.103 g

so 1 troy ounce is heavier than 1 ounce.

8 0
2 years ago
C is the element symbol for which element?<br>a. Carbon<br>b. Cadmium<br>c. Celenium<br>d. Chlorine​
il63 [147K]

Answer:

A) Carbon

Explanation:

the others are wrong its A

6 0
2 years ago
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Temperature (°C)
Andreyy89
The answer is the solution saturated than more dissolved with is C
5 0
2 years ago
At what temperature would 2.10moles of N2 gas have a pressure of 1.25atm and fill a 25.0 L tank
hodyreva [135]

Answer:

\large \boxed{\text{-92 $^{\circ}$C}}

Explanation:

We can use the Ideal Gas Law and solve for T.

pV = nRT

Data  

p = 1.25 atm

V = 25.0 L

n = 2.10 mol

R = 0.082 06 L·atm·K⁻¹mol⁻¹

Calculations

1. Temperature in kelvins

\begin{array} {rcl}pV & = & nRT\\\text{1.25 atm} \times \text{25.0 L} & = & \rm\text{2.10 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\31.25&=&0.09847T\text{ K}^{-1}\\T& = &\dfrac{31.25}{\text{0.098 47 K}^{-1}}\\\\& = &\text{181 K}\end{array}

2. Temperature in degrees Celsius

\begin{array} {rcl}T & = & (181 - 273.15) \, ^{\circ}\text{C}\\& = & -92 \, ^{\circ}\text{C}\\\end{array}\\\text{The temperature of the gas is $\large \boxed{\mathbf{-92 \, ^{\circ}}\textbf{C}}$}

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3 years ago
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