I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1

Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1

Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity

So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity

8 0

2 years ago

Read 2 more answers

Which expression is the factored form of −1.5w+7.5 ?

prohojiy [21]

Answer:

Step-by-step explanation:

the most that can be factored out is -1.5,

-1.5 * w = -1.5w

-1.5 * -5 = 7.5

-1.5w + 7.5, so it's

-1.5(w-5)

8 0

2 years ago

2. The mean birth weight of a full term boy born in the US is 7.7 lbs, with standard deviation of 1.1 lbs. A. Find the probabili

Fed [463]

Answer:

The value is $P( X < 7 ) =0.26226$

The value is $P( X < 7 ) = 0.00073$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 7.7 lbs$

The standard deviation is $\sigma = 1.1 \ lbs$

The sample size is n = 25

Generally the probability that a boy born full term in the US weighs less than 7 lbs is mathematically represented as

$P( X < 7 ) = P( \frac{X - \mu }{\sigma} < \frac{7 - 7.7 }{1.1 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

=> $P( X < 7 ) = P(Z$

From the z table the area under the normal curve to the left corresponding to -0.6364 is

$P(Z$

=> $P( X < 7 ) =0.26226$

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{ 1.1 }{\sqrt{25} }$

=> $\sigma_{x} = 0.22$

Generally the probability that the average weight of 25 baby boys born in a particular hospital have an average weight less than 7 lbs is mathematically represented as

$P( \= X < 7 ) = P( \frac{\= X - \mu }{\sigma_{x}} < \frac{7 - 7.7 }{ 0.22 } )$