I would do this by first listing the multiples of 6 until I start to see a pattern with the one's digit.
6x0=0
6x1=6
6x2=12
6x3=18
6x4=24
6x5=30
6x6=36
6x7=42
6x8=48
...
The digits in bold are the one's digits so those are the only ones we really care about. If you list just them it looks like: 0,6,2,8,4,0,6,2,8
Notice how the first set of 5 numbers seems as though it repeats in the 6th, 7th, and 8th numbers. This probably means the pattern continues infinitely so the first 5 numbers are all the one's digits that can come from multiples of 6. Thus your answer is: 0,6,2,8,or 4
Answer:
Given the domain, the range for 3x-y = 3 is {-9, 6, 9}
Step-by-step explanation:
First you have to put the relation in terms of y ⇒ 3x - y = 3⇒ 3x -3 = y
⇒ y = 3x - 3.
Then you replace the values indicated by the domain to find their "y" values (the ones that constitute the range).
f(-2) = -9
f(2) = 6
f(4) = 9.
Finally, the range for the given domain is {-9, 6, 9}
3 pairs of choices give rise to 2^3 = 8 possibilities:
.. bus, full, morning
.. bus, full, afternoon
.. bus, concession, morning
.. bus, concession, afternoon
.. train, full, morning
.. train, full, afternoon
.. train, concession, morning
.. train, concession, afternoon
3/5*3
pretend that 3 has a denominator which is 1
3/5*3/1
mutiply the numerators together
3*3= 9
mutiply the denominators together
5*1= 5
Answer:
9/5, 1.8 and 1 4/5
