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andreev551 [17]
2 years ago
13

Graph the rational function f(x) = 2x+3 ——— X-4

Mathematics
1 answer:
igor_vitrenko [27]2 years ago
6 0

Answer:

Step-by-step explanation:

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A rectangle has a perimeter of 112 centimeters. if the length of the rectangle is 3 times its​ width, find the dimensions of the
ss7ja [257]
112/2=56 (sum of both lengths)
4x=56
x=14

length=42
width=14
7 0
3 years ago
-6/13 - (-7/15)<br> pls solve it for me !!! :)
MAXImum [283]

Answer:

First, make the double negative a positive.

So, (-6/13) + (7/15)

Then multiply the numerator, 6×7=42

And denominator 13×15=195

42/195 simplify by dividing both by 3 so 14/65

8 0
3 years ago
Read 2 more answers
Factor the polynomial completely.<br><br> 9g^2 - 30gh + 25h^2
Bezzdna [24]

Answer:

Step-by-step explanation:

It's a perfect square.

It factors into (3g - 5h)^2

or (3g - 5h)(3g - 5h)

Make sure it is correctly factored.

3g*3g = 9g^2

3g * - 5h  = - 15gh

-5h*3g = - 15gh

5h*5h = 25h^2

These four terms add to 9g^2 - 15gh - 15gh + 25h^2 = 9g^2 - 30gh + 25h^2 which is exactly what you started with.

7 0
3 years ago
What is 27 is what % of 60?
natta225 [31]
Let 27 be x% of 60

so,
x/100 *60 = 27
x = 27*100/60 = 270/6 = 45

So,
27 is <em>45%</em> of 60.
6 0
3 years ago
How to answer this? A farmer had 455 ducks and chickens. He sold 2/5 of the ducks and bought another 104 chickens. As a result,
julia-pushkina [17]

Answer:

(a) 25

(b) $4816

Step-by-step explanation:

Let's say the starting amount of ducks is d, and the starting amount of chickens is c. Since there are only ducks and chickens, we can say that d + c= 455.

Next, the farmer sells 2/5 of the ducks, so we subtract 2/5 of the ducks so that the ending duck amount is d - (2/5)d = (3/5) d

After that, the farmer buys another 104 chickens, so we add 104 chickens to the current amount of chickens to get the ending chicken number as 104+c

Given the ending duck and chicken count, we can say that the ending farm animal count (we can represent this as a) is (3/5)d + 104 + c = a

The number of ducks is 2/3 the total number of animals at the end, so (3/5)d = (2/3)a

Let's list our equations out so it is easier to solve:

d+c = 455

(3/5)d + 104 + c = a

(3/5)d = (2/3)a

We have three equations and need to solve for three variables. One common variable in all three equations is d, so it might help if we put everything in terms of d.

Starting with d+c=455, if we subtract d from both sides, we get c=455-d. We can substitute this in the second equation to get

(3/5)d + 104 + 455 - d = a

-(2/5)d + 559 = a

(3/5)d = (2/3)a

Next, we can substitute for a. If we multiply both sides by 3 and then divide by 2 in (3/5)d = (2/3)a , we get

(9/10)d = a

Substitute that in to the second equation to get

-(2/5)d + 559 = (9/10) d

-(4/10)d + 559 = (9/10) d

add (4/10)d to both sides to isolate the variable and its coefficient

(13/10)d = 559

multiply both sides by (10/13) to isolate the coefficient

d = 430

Therefore, the starting number of ducks is 430 and the starting amount of chickens is 455-430 = 25

For (b), 2/5ths of the ducks are sold, so this is (430) * (2/5) = 172. Each duck is sold for 28 dollars, so this is 172*28=$4816 as the total price

7 0
3 years ago
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