All categories

2 years ago

3x-7>5 Find the solution, please show your work. Thank You!1

Mathematics

2 answers:

miskamm [114]2 years ago

7 0

To find x just change the > to a =
3x-7=5
add 7
3x=12
then divide by 3
x=4

exis [7]2 years ago

5 0

3x-7>5
3x-7=5
5=7=12
12/3=4
x=4

You might be interested in

Priya changed the rate at which water flowed through the faucet. Write an equation that represents the relationship of $$ and $$

abruzzese [7]

Answer:

1x3

Step-by-step explanation:

6 0

2 years ago

How can I work out 30% of (blank) is 60?

mariarad [96]

$0.3x=60\\
x=200$

4 0

3 years ago

A garden is shaped in the form of a regular heptagon (seven-sided), MNSRQPO. A circle with center T and radius 25m circumscribes

Alenkinab [10]

The relationship between the sides MN, MS, and MQ in the given regular heptagon is $\dfrac{1}{MN} = \dfrac{1}{MS} + \dfrac{1}{MQ}$

The area to be planted with flowers is approximately 923.558 m²

The reason the above value is correct is as follows;

The known parameters of the garden are;

The radius of the circle that circumscribes the heptagon, r = 25 m

The area left for the children playground = ΔMSQ

Required;

The area of the garden planted with flowers

Solution:

The area of an heptagon, is;

$A = \dfrac{7}{4} \cdot a^2 \cdot cot \left (\dfrac{180 ^{\circ}}{7} \right )$

The interior angle of an heptagon = 128.571°

The length of a side, S, is given as follows;

$\dfrac{s}{sin(180 - 128.571)} = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)}$

$s = \dfrac{25}{sin \left(\dfrac{128.571}{2} \right)} \times sin(180 - 128.571) \approx 21.69$

$The \ apothem \ a = 25 \times sin \left ( \dfrac{128.571}{2} \right) \approx 22.52$

The area of the heptagon MNSRQPO is therefore;

$A = \dfrac{7}{4} \times 22.52^2 \times cot \left (\dfrac{180 ^{\circ}}{7} \right ) \approx 1,842.94$

$MS = \sqrt{(21.69^2 + 21.69^2 - 2 \times 21.69 \times21.69\times cos(128.571^{\circ})) \approx 43.08$

By sine rule, we have

$\dfrac{21.69}{sin(\angle NSM)} = \dfrac{43.08}{sin(128.571 ^{\circ})}$

$sin(\angle NSM) =\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ})$

$\angle NSM = arcsin \left(\dfrac{21.69}{43.08} \times sin(128.571 ^{\circ}) \right) \approx 23.18^{\circ}$

∠MSQ = 128.571 - 2*23.18 = 82.211

The area of triangle, MSQ, is given as follows;

$Area \ of \Delta MSQ = \dfrac{1}{2} \times 43.08^2 \times sin(82.211^{\circ}) \approx 919.382^{\circ}$

The area of the of the garden plated with flowers, $A_{req}$ , is given as follows;

$A_{req}$ = Area of heptagon MNSRQPO - Area of triangle ΔMSQ

Therefore;

$A_{req}$ = 1,842.94 - 919.382 ≈ 923.558

The area of the of the garden plated with flowers, $A_{req}$ ≈ 923.558 m²

Learn more about figures circumscribed by a circle here:

brainly.com/question/16478185

6 0

2 years ago

-9x^5 + 36x^4 + 189x^3 in factored form

Alex73 [517]

Answer:

-9x^5(x+3)(x-7)

Step-by-step explanation:

factor out -9x^3 from the expression

8 0

3 years ago

86° 34° Х X = ____ degrees help quick pls

Rufina [12.5K]

Answer:

60 degrees

Step-by-step explanation:

The angles all have to add up to 180, so you can do

$34 + 86 +x = 180\\120 + x = 180\\x = 60$

3 0

2 years ago

Read 2 more answers