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3 years ago

Can someone explain to me how to find mean/median of a data set real quick?

2 answers:

8 0

The median of a set of data is the middlemost number in the set. The median is also the number that is halfway into the set. To find the median, the data should first be arranged in order from least to greatest.

To find the mean, add up all of the numbers in the set and divide by the number of values that you added. Then, divide by the number of values

PIT_PIT [208]3 years ago

3 0

Mean is were you add up all of the numbers and how many numbers are there thats how much you divide by and median is were you line up the numbers from least to greatest then try to find the middle number

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Someone help me pls,I need the value of both x and y

zlopas [31]

Answer
Y=10 x=9
Explanation
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1 year ago

Which of the following is represented by ST?D.circumference c radius B center A Diameter

Kitty [74]

Answer:

C. Radius

Explanation:

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3 years ago

Read 2 more answers

What is the distance between (-4,-8) and (-4,0) round to the nearest tenth if needed

mixer [17]

Answer:

Step-by-step explanation:

Distance between x coordinates: 0 units

Distance between y coordinates: 8 units

sqrt(0^2+8^2)

8 units

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3 years ago

I need help with this question. I didn't choose answer D, but I accidentally did. If you could help me, that would be great.

Alex

Answer:

The correct answer would be B

Step-by-step explanation:

Plz Mark Brainlist

7 0

3 years ago

How do i prove 2sec^2x-2sec^2xsin^2-sin^2x-cos^2x=1

kramer

$2\sec^2x-2\sec^2x\sin^2x-\sin^2x-\cos^2x=2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)$

Since $\sin^2x+\cos^2x=1$ , you have

$2\sec^2x(1-\sin^2x)-(\sin^2x+\cos^2x)=2\sec^2x\cos^2x-1$

and since $\sec x=\dfrac1{\cos x}$ , you end up with $2-1=1$ .

6 0

3 years ago