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Klio2033 [76]
4 years ago
11

How many 5-letter words that have the letter 'x' are possible? Letters may be repeated, and the words don't have to be meaningfu

l. (Hint: First count the words without 'x' .) Your answer is:
Mathematics
1 answer:
aliya0001 [1]4 years ago
5 0

Answer:

2115751

Step-by-step explanation:

Solution:

- The number of 5 letter words that contain x is the number of 5 letter words overall minus the number of 5 letter of words without x.

                  How many 5 letter words are there overall?

- The first letter could be one of 26 letters. The same could be said about the second letter, and the third, and the fourth and the fifth .. so on.

- So the number of 5 letter words overall is:

                        26x26x26x26x26 = 26^5 = 11881376

          How many 5 letter words are there that do not contain x?

- The first letter could be one of 25 letters (it could be one of any of the other 25 letters but not x). The second letter could also be one of 25 letters, and so could the third, and so could the fourth, and so could the fifth.

- So the number of 5 letter words that do not contain x is:

                        25x25x25x25x25 = 25^5 = 9765625

- So the number of 5 letter words that contain x is:

                      26^5 - 25^5 = 11881376 - 9765625 = 2115751.

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Step-by-step explanation:

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a dog searching for a bone walks 3.5 m southeast, then 8.2 m at an angle 30 degrees north of east. Find the magnitude of the dog's resultant vector

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Answer:

Step 1: Firstly, we draw both of the axes.

Step 2: We then draw a vector of length 3.5 m (theoretical) along the (-x) axis.

Step 3: Next, we draw a vector of length 8.2 m from the endpoint towards to top, at an angle of 60° from that point (N.B: 90-30, since it is required to make a 30°∠ with the current vertical; eventually the triangle being formed will be 90° minus the 30°.) Most importantly, the 8.2 m vector should be drawn in such a way so that it is higher than the starting point of the 3.5 m vector. )

Step 4: Lastly, we draw a 15 m vector from the endpoint of the 8.2 m vector, running above the original vector, and to the left. This one should be drawn on the left side, and must be situated far enough.

∴ Triangle 1 () is of angles 30°, 60° and 90°;

On solving for the vertical side (the slope similar to the 3.5 vector), we get

(8.2/2) m = 4.1 m

Next, we solve for the opposite side via 4.1 × √3= 7.1 m

Moving on to Triangle 2 (),

top side = (15 - 7.1) m = 7.9 m

similarly, right side = (4.1 - 3.5) m = 0.6 m

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Given:

Markers are sold in packages of 12 and pens are sold in packages of 8.

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Least amount of markers and pens Rick needs to buy to have an equal number of markers and pens

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Prime factors of 8 and 12 are

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To find the LCM, multiply all factors but the common factors are included only once.

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