Locate the mean of 2046,971,3113,and 1850.

1 answer:

7 0

To find the mean, you have to add all the numbers then divide it by how many numbers there are.

In this case, you'll need to add all those numbers and divide it by 4.
$2046+971+3113+1850=7980\\7980\div4=1995$

The mean is 1995.

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In a survey of U.S. adults with a sample size of 2062,330said Franklin Roosevelt was the best president since World War II. Two

tigry1 [53]

Answer:

a) 0.0255

b) 0.7050

c) 0.2945

Step-by-step explanation:

Probability that one of those sampled saying that Roosevelt was the best president since World War II = 330/2062 = 0.16

Probability that one of those sampled don't mention Roosevelt = (2062 - 330)/2062 = 1732/2062 = 0.84

a) The probability that both adults picked say Franklin Roosevelt was the best president since World War II = (330/2062) × (329/2061) = 0.0255

b) The probability that neither of the two adults say Franklin Roosevelt was the best president since World War II = (1732/2062) × (1731/2061) = 0.7050

c) The probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II = Probability that one of the two adults mention Roosevelt + Probability that the two adults mention Roosevelt

Probability that one of the adults mention Roosevelt = [(330/2062) × (1732/2061)] + [(1732/2062) × (330/2061)] = 0.269

Probability that two of the adults mention Roosevelt has been done in (a) and it is equal to 0.0255

probability that at least one of the two adults says Franklin Roosevelt was the best president since World War II = 0.269 + 0.0255 = 0.2945

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3 years ago

I will give Brainliest

Pachacha [2.7K]

69 points hahahahaha

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