Question

What is the poinet-slope form of the equation for the line in the graph?​

Answer 1

Answer:

$y -5 = \frac{9}{13}(x - 7)$

Step-by-step explanation:

Given :

Two points are given in graph (-6, -4) and {7, 5).

The point-slope form of the equation of a straight line is:

$y -y_{1} = m(x - x_{1})$------------(1)

Let $(x_{1}, y_{1})=(7,5)$ and $(x_{2}, y_{2})=(-6,-4)$

The slope of the line $m=\frac{y_{2}- y_{1}}{x_{2}- x_{1}}$

Put all known value in above equation.

$m=\frac{-4- 5}{-6- 7}$

$m=\frac{-9}{-13}$

$m=\frac{9}{13}$

The slope of the line $m=\frac{9}{13}$

We know m, and also know that $(x_{1}, y_{1})=(7,5)$, so we put these value in equation 1.

$y -5 = \frac{9}{13}(x - 7)$

Therefore, the equation of the line is $y -5 = \frac{9}{13}(x - 7)$.