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3 years ago

8r-5q=3, solve for q

Mathematics

2 answers:

Stella [2.4K]3 years ago

5 0

Subtract 8r over so it becomes
-5q=3-8r

Then divide both sides by -5
q= (3-8r)/-5

steposvetlana [31]3 years ago

5 0

8r-5q=3
-5q=3-8r
5q= -3+8r
q= -3/5 + 8r/5

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Step-by-step explanation:

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Read 2 more answers

How to prove this???

swat32

$\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3) \\
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$

go to right side now

$4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)$

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$4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
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4 0

3 years ago

3² +4² = 5²,

AlekseyPX

Answer:

They are all true

Step-by-step explanation:

1. 3² +4² = 5²

3x3 + 4x4 = 5x5

9 + 16 = 25

25 = 25

-----------------------

2. 6² + 8² = 10²

36 + 64 = 100

100 = 100

------------------

3. 9² + 12² = 15²

81 + 144 = 225

225 = 225

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4. 5² +12² =13²

25 + 144 = 169

169 =169

-------------------

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Answer:

---

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