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Tresset [83]
3 years ago
11

Please help me. thank you!

Mathematics
2 answers:
KonstantinChe [14]3 years ago
7 0

Answer:

thanks for the points lol

Step-by-step explanation:

emmainna [20.7K]3 years ago
3 0

Answer:

x= -10

Step-by-step explanation:

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Last year Mr. Ingles total income was 52000+ total expenses were 53800 use expression I-E/12 where I represents total income in
Olegator [25]

Answer:

-$150

Step-by-step explanation:

Given:

(I - E) / 12

Where,

I = total income

E = total expenses

I = $52,000

E = $53,800

(I - E) / 12

= (52,000 - 53,800) / 12

= -1,800 / 12

= -150

-$150 shows that Mr. Engle's total expenses exceeds his total income per month with an average of $150

8 0
3 years ago
Find the radiys of circle J. Segment KL has a length of 8 (ROUND YOUR ANSWER TO THE NEAREST TENTH)
FrozenT [24]

To find the x, let's look at the sketch below:

All we simply need to do is to use Pythagorars theorem to find y

x is a radius and y is also a radius

Hence x and y are congruent

So Using Pythagoras theorem

y² = 3.6² + 4²

y² = 12.96 + 16

y² = 28.96

Take the square root of both-side of the equation

y ≈ 5.4

Therefore, x= 5.4

5 0
2 years ago
Graph the follow in equation
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8 0
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Two lines are intersecting. What is the value of X? And to your answer in the box
Goshia [24]
X= 51 is the answer you need to remember that since they share a straight line you add the together to get 180 which is half a circle
7 0
3 years ago
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A university dean is interested in determining the proportion of students who receive some sort of financial aid. Rather than ex
Olenka [21]

Answer:

a

 The  90% confidence interval that  estimate the true proportion of students who receive financial aid is

     0.533  <  p <  0.64

b

   n = 1789

Step-by-step explanation:

Considering question a

From the question we are told that

      The sample size is  n = 200

      The number of student that receives financial aid is k = 118

Generally the sample proportion is  

      \^ p = \frac{k}{n}

=>   \^ p = \frac{118}{200}

=>   \^ p = 0.59

From the question we are told the confidence level is  90% , hence the level of significance is    

      \alpha = (100 - 90 ) \%

=>   \alpha = 0.10

Generally from the normal distribution table the critical value  of \frac{\alpha }{2}  is  

   Z_{\frac{\alpha }{2} } =  1.645

Generally the margin of error is mathematically represented as  

     E =  Z_{\frac{\alpha }{2} } * \sqrt{\frac{\^ p (1- \^ p)}{n} }

 =>E =  1.645 * \sqrt{\frac{0.59 (1- 0.59)}{200} }

=>  E = 0.057

Generally 90% confidence interval is mathematically represented as  

      \^ p -E <  p <  \^ p +E

  =>  0.533  <  p <  0.64  

Considering question b

From the question we are told that

    The margin of error  is  E = 0.03

From the question we are told the confidence level is  99% , hence the level of significance is    

      \alpha = (100 - 99 ) \%

=>   \alpha = 0.01

Generally from the normal distribution table the critical value  of   is  

   Z_{\frac{\alpha }{2} } = 2.58

Generally the sample size is mathematically represented as      

        [\frac{Z_{\frac{\alpha }{2} }}{E} ]^2 * \^ p (1 - \^ p )

=>      n = [\frac{2.58}{0.03} ]^2 * 0.59 (1 - 0.59 )

=>      n = 1789

8 0
3 years ago
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