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stiv31 [10]
3 years ago
14

Solve for the variable

Mathematics
1 answer:
jolli1 [7]3 years ago
6 0
Step 1: -6a + 3 = -3(2a - 1)
Step 2: -6a + 3 = -3(2a) + 3(1)
Step 3: -6a + 3 = -6a + 3
Step 4:+6a         +6a
Step 5:          3 = 3

The variable of x is equal to Any infinite number.
You might be interested in
If Florist B increases the cost per rose to $5.20,for what number of roses is it less expensive to order from Florist A? From Fl
Alenkinab [10]

Answer:

For<em> </em>38 roses at <em>$5.15</em> per rose, Florist A is Less Expensive then Florist B

For<em> </em>34 roses at <em>$5.20</em> per rose, Florist A is Less Expensive then Florist B

Step-by-step explanation:

The Full Question Reads:

<u><em>Derek wants to order some roses online.  Florist A charges $4.75 per blue rose plus $40 delivery charge.  Florist B charges $5.15 per red rose plus $25 delivery charge.  If Florist B increases the cost per rose to $5.20, for what number of roses is it less expensive to order from Florist A?  From Florist B?</em></u>

To begin we need to understand our given information and what we are actually looking for.

<u>Given Information</u>

Florist A:

charges $4.75 per blue rose

charges $40 per delivery

Florist B:

charges $5.15 per red rose

charges $25 per delivery

Note: in this problem we ignore the colour of the rose (red or blue) as it does not affect our solution or contributes to it. Therefore we shall call our first variable representing the number of roses as x.

The next step is to construct a system of equations representing our problem and our given information. Here we are looking at linear relationships so a linear function of the form:

y=ax+b   Eqn(1).

<em>will suffice where</em>

y: represents the total cost from the Florists (i.e. number of roses and delivery charges). Dependent Variable

x: represents the number of roses purchased from the Florists. Independent Variable

a: is our relationship factor between y and x

b: is our constant which in this problem is the <em>delivery charge</em> value for each florist.  

Since we have two Florists, we will construct two equations, one for each florist, by employing Eqn(1).  and our given information as follow:

Florist A:  y=4.75x+40   Eqn(2).

Florist B:  y=5.15x+25   Eqn(3).

By employing both equations above and writing them as an inequality <em>since we are looking for which value of </em>x<em> (i.e. number of roses) will the less expensive Florist be and then solving for </em>x<em> we have: </em>

<em>4.75x+40</em>

<em>4.75x-5.15x       Gathering all similar terms together</em>

<em>-0.4x                       Simplifying</em>

<em>x>\frac{-15}{-0.4}\\                             Solving for x </em>

<em>x>37.5</em>

<em>(note how < changes to > since any multiplication/devision process of negative sign in an Inequality will change the order of < to > and vice versa). </em>

Since a rose has to be sold as a whole and not half we will say that <em>x>38</em> So we can then plug in the value of x in Eqn(2) and Eqn(3) and find the cost of buying more than 38 roses from each:

Eqn(2):  Florist A:  y(x>38)=4.75*38+40=220.5  

Eqn(3):  Florist B:  y(x>38)=5.15*38+25=220.7

Which tells us that Florist A is less expensive than Florist B by $0.20 for a purchase of more than 38 roses.

Next the question tells us that Florist B increases the cost from $5.15 to $5.20 per rose, which in Eqn(3) denotes our a value and thus Eqn(3). now becomes:

Florist B:  y=5.20x+25   Eqn(3).

Applying the same method like before and solving for the value of x<em> we have: </em>

<em>4.75x+40</em>

<em>4.75x-5.20x       Gathering all similar terms together</em>

<em>-0.45x                       Simplifying</em>

<em>x>\frac{-15}{-0.45}\\                           Solving for x </em>

<em>x>33.3</em>

Similarly as a rose has to be sold as a whole and not half we will say that <em>x>34</em> So we can then plug in the value of x in Eqn(2) and Eqn(3) and find the cost of buying more than 34 roses from each:

Eqn(2):  Florist A:  y(x>34)=4.75*34+40=201.5  

Eqn(3):  Florist B:  y(x>34)=5.15*34+25=201.8

Which tells us that Florist A is again less expensive than Florist B by $0.30 for a purchase of more than 34 roses. It was also shown that as the cost of the rose increased by $0.05 the number of roses for purchase decreased.

4 0
3 years ago
12345678910111213141516
Galina-37 [17]

Step-by-step explanation:

oh, come on. you can just use common sense.

a local minimum is a point where the curve goes down to, and then turns around and starts to go up again. that point in the middle, where it turns around and does not go down any further, is the minimum.

for the maximum the same thing applies, just in the other direction (the curve goes up and turns around to go back down again).

a)

the local minimum values (y) are

-2, -1

b)

the values of x where it had these minimum values are

-1, +3

4 0
2 years ago
Simplify the variable expression by evaluating its numerical part.
Virty [35]
You can use this one app it’s called Cymath it’s really helpful with these types of problems,
6 0
3 years ago
Explore the properties of angles and arcs
marshall27 [118]

Answer:

80-24=56

28 multiplied by 2=56

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Beef hope me I need you to answer the question. What is n * 54 - 688-20 =???³
blsea [12.9K]

Answer:n= 1/3d - 2/3m

Step-by-step explanation:

d=2m+3n

Step 1: Flip the equation.

2m+3n=d

Step 2: Add -2m to both sides.

2m+3n+−2m=d+−2m

3n=d−2m

Step 3: Divide both sides by 3.

3n/3 = d-2m/3

Therefore

n= 1/3d - 2/3m

Hope this helps!

Plz name brainliest if possible.

1jaiz4 and 1 more users found this answer helpful

THANKS

1

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Answer

0

maxtext75

Helping Hand

15 answers

26 people helped

Answer:

n = d - 2m

        3*

Step-by-step explanation:

First we want to get n alone on one side, so we should subtract 2m from both side;

d = 2m + 3n

3n = d - 2m

Now to get n by itself, we need to divide by 3 from both sides;

3n = d - 2m

n = d - 2m

        3*

*Pretend there is a fraction bar between d - 2m and 3

Step-by-step explanation:

7 0
3 years ago
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