Question

Graph the line with slope -2/3 passing through the point (-2,2).

Answer 1

Answer:

The graph is shown below.

Step-by-step explanation:

Given:

Slope of the line is, $m=-\frac{2}{3}$

A point on the line is (-2,2).

Let us find the equation of a line using the point-slope form:

$y-y_1=m(x-x_1)$

Here, $x_1=-2,y_1=2,m=-\frac{2}{3}$

$y-2=-\frac{2}{3}(x-(-2))\\y-2=-\frac{2}{3}(x+2)\\3(y-2)=-2(x+2)\\3y-6=-2x-4\\2x+3y=-4+6\\2x+3y=2$

Let $x=1$, then

$2(1)+3y=2\\2+3y=2\\3y=0\\y=0$. So, a point is (1,0).

Another point is given as (-2,2)

Now, draw a line passing through these two points. This is the graph of the required line.