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3 years ago

Simplify 19 - 1.67 + (2.4)

Mathematics

2 answers:

alexandr1967 [171]3 years ago

6 0

Answer:

19.73.

Step-by-step explanation:

Given : 19 - 1.67 + (2.4).

To find : simplify.

Solution : We have given 19 - 1.67 + (2.4).

By the BODMAS rule :

First we open the parenthesis

19 - 1.67 + 2.4

Now we solve the addition operation

19+2.4 -1.67

21.4 -1.67.

Now we will solve the subtraction operation :

19.73.

Therefore, 19.73.

natali 33 [55]3 years ago

3 0

The answer is 19.73 because 19 minus 1.67 is 17.33 and 17.33 plus 2.4 is 19.73

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The function f(t) = −5t 2 + 20t + 60 models the approximate height of an object

kakasveta [241]

Plug in f(t) = 0. We do this because f(t) represents the height and a height of 0 means you're at the ground.

f(t) =-5t^2 + 20t + 60

0 = -5t^2 + 20t + 60

-5t^2 + 20t + 60 = 0

Now solve for t using the quadratic formula

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4 years ago

Is the perpendicular bisector of . if ac = 4x and bc = 6x – 10, what is the value of x?

Masteriza [31]

6x - 10 = 4x
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4 years ago

11x - 12 = 16 + 12x What’s the answer lol

Mice21 [21]

Answer:

x = -28

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients

Step-by-step explanation:

Step 1: Define

11x - 12 = 16 + 12x

Step 2: Solve for x

[Subtraction Property of Equality] Isolate x terms: -12 = 16 + x
[Subtraction Property of Equality] Isolate x: -28 = x
Rewrite: x = -28

5 0

3 years ago

Read 2 more answers

Use the drawing below to answer the questions that follow.

zhannawk [14.2K]

you have to multiple 16 i think

8 0

3 years ago

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In simplest radical form, what are the solutions to the quadratic equation 0 =3x4x + 5?

morpeh [17]

Given:

The quadratic equation is

$0=-3x^2-4x+5$

To find:

The simplest radical form of the solution.

Solution:

Quadratic formula:

If a quadratic equation is $ax^2+bx+c=0$ , then

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

We have,

$0=-3x^2-4x+5$

Here, a=-3, b=-4 and c=5. Putting these values in the quadratic formula, we get

$x=\dfrac{-(-4)\pm \sqrt{(-4)^2-4(-3)(5)}}{2(-3)}$

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$x=\dfrac{4\pm \sqrt{76}}{-6}$

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Taking 2 common, we get

$x=\dfrac{2(2\pm \sqrt{19})}{-6}$

$x=\dfrac{(2\pm \sqrt{19})}{-3}$

$x=-\dfrac{(2\pm \sqrt{19})}{3}$

Therefore, the correct option is A.

7 0

3 years ago