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Bezzdna [24]
3 years ago
11

How to reduce 30/66?

Mathematics
1 answer:
stich3 [128]3 years ago
8 0
You reduce 30/66 by dividing the numerator and the denominator by the same number, which in this case will be 2. When you reduce you should get 15/33 which you can reduce again to 5/11.
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Multiply the two polynomials and write your answer in Standard form -3x(4x-2)
Tatiana [17]

Answer:

24

Step-by-step explanation:

-3x(4x-2)

-3*-8

+24

-*-=+

+*-=-

-*+=-

3 0
3 years ago
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Solve the following system of linear equations: 3x1+6x2+6x3 = -9 -2x1–3x2-3x3 = 3 If the system has infinitely many solutions, y
choli [55]

Answer:

The set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

Step-by-step explanation:

The augmented matrix of the system is \left[\begin{array}{ccccc}3&6&6&-9\\-2&-3&-3&3\end{array}\right].

We will use rows operations for find the echelon form of the matrix.

  • In row 2 we subtract \frac{2}{3} from row 1. (R2- 2/3R1) and we obtain the matrix \left[\begin{array}{cccc}3&6&6&-9\\0&1&1&-7\end{array}\right]
  • We multiply the row 1 by \frac{1}{3}.

Now we solve for the unknown variables:

  • x_2+x_3=-7, x_2=-7-x_3
  • x_1+2x_2+2x_3=-2, x_1+2(-7-x_3)+2x_3=-2 then x_1=12

The system has a free variable, the the system has infinite solutions and the set of solutions is \{\left[\begin{array}{c}x\\y\\z\end{array}\right]=\left[\begin{array}{c}12\\-7-r\\r\end{array}\right]: \text{r is a real number}  \}

6 0
3 years ago
Solve the equation. 3 (x - 1) = 18
In-s [12.5K]
  • 3 ( x - 1 ) = 18
  • or, 3x - 3 = 18
  • or, 3x = 18 - 3
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  • or, x = 15 ÷ 3
  • or, x = 5

<u>Answer</u><u>:</u>

<u>x </u><u>=</u><u> </u><u>5</u>

Hope you could understand.

If you have any query, feel free to ask.

4 0
2 years ago
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Can someone help me please
Vadim26 [7]

Answer:

the second friend

Step-by-step explanation:

3 0
3 years ago
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(50 points and Brainiest
Scorpion4ik [409]

could you possibly make two zoomed in pictures?

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