All you need to do for this is 155-75 which would be 80 :) hope this helps
Answer:
Total wrapping papers Serena and her grandmother = 51/10
Step-by-step explanation:
Serena's wrapping paper for parents:
sq meters
Grandmother's wrapping paper:
sq meters
In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.
i.e.
Total papers = Serena's wrapping paper + Grandmother's wrapping paper





Therefore, total wrapping papers Serena and her grandmother = 51/10
20 / 27 is the probability that a student chosen randomly from the class passed the test or completed the homework.
<u>Step-by-step explanation:</u>
To find the probability that a student chosen randomly from the class passed the test or complete the homework :
Let us take,
- Event A ⇒ a student chosen randomly from the class passed the test
- Event B ⇒ a student chosen randomly from the class complete the homework
We need to find out P (A or B) which is given by the formula,
⇒ P (A or B) = P(A) + P(B) - P(A∪B)
<u>From the given table of data,</u>
- The total number of students in the class = 27 students.
- The no.of students passed the test ⇒ 15+3 = 18 students.
P(A) = No.of students passed / Total students in the class
P(A) ⇒ 18 / 27
- The no.of students completed the homework ⇒ 15+2 = 17 students.
P(B) = No.of students completed the homework / Total students in the class
P(B) ⇒ 17 / 27
- The no.of students who passes the test and completed the homework = 15 students.
P(A∪B) = No.of students both passes and completes the homework / Total
P(A∪B) ⇒ 15 / 27
Therefore, to find out the P (A or B) :
⇒ P(A) + P(B) - P(A∪B)
⇒ (18 / 27) + (17 / 27) - (15 / 27)
⇒ 20 / 27
∴ The P (A or B) is 20/27.
Answer:
The answer is B. 4cm
Step-by-step explanation:
Since it is the midpoint AC is always going to be the same as CB if C is the midpoint.
:)
Answer:
90 degrees clockwise rotation about the origin
Step-by-step explanation:
<u>As per the graph we can see transition of:</u>
- 90 degrees clockwise rotation about the origin
- Original quadrilateral IJKL
- Image quadrilateral I'J'K'L'
Rule applied to each point: