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8090 [49]
3 years ago
8

A radio station had 192 tickets to a concert. they gave away 5 times as many tickets to listeners as to the employees. how many

tickets did they give away to employees?
A. 32
B.6
C.37
D.5
Mathematics
1 answer:
Nostrana [21]3 years ago
8 0

Answer: OPTION A.

Step-by-step explanation:

Let be "e" the number of tickets that the radio station gave away to employees and "l" the number of tickets that the radio station gave away to listeners.

Based on the data given in the exercise, you can set up the following System of equations:

\left \{ {{e+l=192 } \atop {l=5e}} \right.

Finally you must apply the Substitution Method to solve the System of equations.

To apply it, you must substitute the second equation into the first one and then you must for the variable "e".

Through this precedure you get the following value of "e":

e+l=192\\\\e+(5e)=192\\\\6e=192\\\\e=\frac{192}{6}\\\\e=32

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Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin
levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

  • 3\frac{3}{5}=\frac{18}{5} sq meters

Grandmother's wrapping paper:

  • 1\frac{1}{2}=\frac{3}{2} sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

                     =\frac{18}{5}+\frac{3}{2}

                     =\frac{36}{10}+\frac{15}{10}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

                      =\frac{36+15}{10}

                      =\frac{51}{10}

Therefore, total wrapping papers Serena and her grandmother = 51/10

3 0
2 years ago
In a class of students, the following data table summarizes how many students passed a test and complete the homework due the da
Alexxandr [17]

20 / 27 is the probability that a student chosen randomly from the class passed the test or completed the homework.

<u>Step-by-step explanation:</u>

To find the probability that a student chosen randomly from the class passed the test or complete the homework :

Let us take,

  • Event A ⇒ a student chosen randomly from the class passed the test
  • Event B ⇒ a student chosen randomly from the class complete the homework

We need to find out P (A or B) which is given by the formula,

⇒ P (A or B) = P(A) + P(B) - P(A∪B)

<u>From the given table of data,</u>

  • The total number of students in the class = 27 students.
  • The no.of students passed the test ⇒ 15+3 = 18 students.

P(A) = No.of students passed / Total students in the class

P(A) ⇒ 18 / 27

  • The no.of students completed the homework ⇒ 15+2 = 17 students.

P(B) = No.of students completed the homework / Total students in the class

P(B) ⇒ 17 / 27

  • The no.of students who passes the test and completed the homework = 15 students.

P(A∪B) = No.of students both passes and completes the homework / Total

P(A∪B) ⇒ 15 / 27

Therefore, to find out the P (A or B) :

⇒ P(A) + P(B) - P(A∪B)

⇒ (18 / 27) + (17 / 27) - (15 / 27)

⇒ 20 / 27

∴ The P (A or B) is 20/27.

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2 years ago
In the diagram below, C is the midpoint of AB. If AC is 4 centimeters, what is
Strike441 [17]

Answer:

The answer is B. 4cm

Step-by-step explanation:

Since it is the midpoint AC is always going to be the same as CB if C is the midpoint.

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Answer:

90 degrees clockwise rotation about the origin

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<u>As per the graph we can see transition of:</u>

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Rule applied to each point:

  • (x, y) -------> (y, -x)
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