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Tomtit [17]
3 years ago
15

Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin

g paper do Serena and her grandmother have together
Mathematics
1 answer:
levacccp [35]3 years ago
3 0

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

  • 3\frac{3}{5}=\frac{18}{5} sq meters

Grandmother's wrapping paper:

  • 1\frac{1}{2}=\frac{3}{2} sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

                     =\frac{18}{5}+\frac{3}{2}

                     =\frac{36}{10}+\frac{15}{10}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}

                      =\frac{36+15}{10}

                      =\frac{51}{10}

Therefore, total wrapping papers Serena and her grandmother = 51/10

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Una librería consta de 5400 libros repartidos en 3 estanterías
pishuonlain [190]

Answer:

B = 900 Libros

A = 2700 Libros

C = 1800 Libros

Step-by-step explanation:

A = 3B

2B = C

A + B + C = 5400

3B + B + 2B = 5400

6B = 5400

B = 5400 / 6

B = 900 Libros

A = 3B

A = 3(900)

A = 2700 Libros

C = 2B

C = 2(900)

C = 1800 Libros

7 0
3 years ago
(II) Time intervals measured with a stopwatch typically have an uncertainty of about 0.2 s, due to human reaction time at the st
Reil [10]

Answer:

(a) 36.36%

(b) 0.36%

(c) 0.06%

Step-by-step explanation:

Given that the time intervals measured with a stopwatch have an uncertainty of about 0.2 s.

We want to know what is the percent uncertainty of a hand-timed measurement of:

(a) 5.5 s

Percentage = (0.2/5.5) × 100

≈ 36.36%

(b) 55 s

Percentage = (0.2/55)×100

≈ 0.36%

(c) 5.5 min

5.5 min = 5.5 × 60 s

= 330 s

Percentage = (0.2/330)×100

≈ 0.06%

5 0
3 years ago
Find the cost of flooring a square shaped room of side 10m at a rate of Rs.50 per square meter.
Ierofanga [76]
<h3>Explanation:</h3>

We have to find the area of the square shaped room.

<h3>Given:</h3>

Side of the square shaped room = 10 m

The cost of flooring a square metre is Rs. 50

<h3>To Find:</h3>

The cost of flooring a square shaped room.

<h3>Formula:</h3>

Area of square = Side × Side

<h3>Solution:</h3>

Area of the square = 10 × 10 = 100 sq.m

1 sq.m = Rs. 50

100 sq.m = 50(100) = Rs. 5,000

<h2>Answer:</h2>

The cost of flooring a square shaped room of side 10 m is <u>Rs. 5,000</u><u>.</u>

6 0
3 years ago
The graphs of the equations y=2x-7 and y-kx=7 are parallel when k equals
Slav-nsk [51]
y=2x-7 \ and \ y-kx=7 \\ \\ y=2x-7 \ and \ y=kx+7 \\ \\ two \ lines \ are \ parallel \ if \ their \ slopes \ are \ the \ same : \\ \\ k= 2


7 0
3 years ago
What is the product of (-3s+2t(4s-t)
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Use the FOLD method<span>
(a+b)(c+d)=ac+ad+bc+bd

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</span></span></span></span>Collect like terms
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Simplify
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The answer is = -12s^2 + 11st - 2t^2</span></span></span></span></span>
5 0
3 years ago
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