Answer:
the answer is c
Step-by-step explanation:
OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Answer:
2
Step-by-step explanation:do it on a piese of parer them it will make more sence
The answer is 1/45. Hope that helps
Answer:
277,200
Step-by-step explanation:
To find the number of permutation we can form from the letters of the word "engineering", we first need to find the frequencies of the different letters present.
E = 3
G = 2
N= 3
I = 2
R = 1
Now that we have the frequencies, we count the number of letters in the word "engineering".
E N G I N E E R I N G
11 letters
Now we take the factorial of total number of letters and divide it by the number of repeats and their factorial
So we get:

We remove the 1! because it will just yield 1.

So the total number of permutations from the letters of the word "engineering" will be:
Total number of permutations = 
Total number of permutations = 277,200