Answer:
The expected value of random variable X is often written as E(X) or µ or µX.
Step-by-step explanation:The expected value is the 'long-run mean' in the sense that, if as more and more values of the random variable were collected (by sampling or by repeated trials of a probability activity), the sample mean becomes closer to the expected value.
Answer:
The all common Factors of 24 are 1, 2, 3, 4, 6, 8, 12 and 24
The answer to 3) is: x = ±7
Break down the problem into these 2 equations:
x/7 = 1 and -x/7 = 1
Then solve both equation and collect all solutions.
Let me know if this helped you! Good luck Bella4992!
PEMDAS
multiply 2x2=4 and simplify the equation by looking for like terms to combine.
4+16x+y+34=0
4 and 34 are like terms so add them.
the simplified expression is 16x+y+38
The given inequality holds for the open interval (2.97,3.03)
It is given that
f(x)=6x+7
cL=25
c=3
ε=0.18
We have,
|f(x)−L| = |6x+7−25|
= |6x−18|
= |6(x−3)|
= 6|x−3|
Now,
6|x−3| <0.18 then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03
the given inequality holds for the open interval (2.97,3.03)
For more information on inequality click on the link below:
brainly.com/question/11613554
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Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.
f(x)=6x+7,L=25,c=3,ϵ=0.18
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