Find the exact length of the third side. 75 21
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The question is incomplete, here is the complete question:
Recall that m(t) = m.(1/2)^t/h for radioactive decay, where h is the half-life. Suppose that a 500 g sample of phosphorus-32 decays to 356 g over 7 days. Calculate the half life of the sample.
<u>Answer:</u> The half life of the sample of phosphorus-32 is
<u>Step-by-step explanation:</u>
The equation used to calculate the half life of the sample is given as:
where,
m(t) = amount of sample after time 't' = 356 g
= initial amount of the sample = 500 g
t = time period = 7 days
h = half life of the sample = ?
Putting values in above equation, we get:
Hence, the half life of the sample of phosphorus-32 is
So. let's say the numbers are "a" and "b"
whatever they're, we know a + b = 56
let's say the larger one is "b", so 3 times the smaller is 3*a or 3a
now, 12 less than that, is 3a - 12
and the larger is that, so b = 3a - 12
so
solve for "a", to see what the smaller one is
what's b? well, b = 56 - a
whatever they're, we know a + b = 56
let's say the larger one is "b", so 3 times the smaller is 3*a or 3a
now, 12 less than that, is 3a - 12
and the larger is that, so b = 3a - 12
so
solve for "a", to see what the smaller one is
what's b? well, b = 56 - a