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Olenka [21]
3 years ago
15

In some year, two towns A and B had same population but after

Mathematics
1 answer:
almond37 [142]3 years ago
7 0

Answer:

The answer is 25%

Step-by-step explanation:

on the first year lets say town A and town B had a population of 100 (a town wouldn't have only 100 people but for simplicity lets do 100).

town A's population increases by 60%, 60% of 100 is 60, 100 + 60 = 160

town B's population decreases by 60%, 100 - 60 = 40

so now we have town A's population after 10 years and town B's population after 10 years, 160 divided by 40 = 4, and 100 divided by 4 equals 25, so the answer is 25%.

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Step-by-step explanation:

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Step-by-step explanation:

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_____

<em>Comment on the problem</em>

It seems more likely that the proportion should be written as ...

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or

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3 0
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Suppose that the probabilities of a customer purchasing​ 0, 1, or 2 books at a book store are 0.2​, 0.3​, and 0.5​, respectively
svetlana [45]

Answer:

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