Solve the equation using distribution, combining like terms, transforming variables on both sides, and solving two step equation
1 answer:
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The equation of the table is a linear function; which has a constant rate of change
<h3>How to complete the table</h3>The equation is given as:
y = 2x + 3
When x = -2, we have:
When x = 0, we have:
When x = 1, we have:
When x = 3, we have:
So, the complete table is:
x -2 -1 0 1 2 3
y -1 1 3 5 7 9
<h3>The graph of the equation</h3>See attachment for the graph of y = 2x + 3
Read more about linear functions at:
Answer:
There is an 88% probability that a course has a final exam or a research paper.
Step-by-step explanation:
We solve this problem building the Venn's diagram of these probabilities.
I am going to say that:
E is the probability that a course has final exam.
P is the probability that a course requires research paper.
We have that:
In which e is the probability that a course has final exam but does not require research paper and is the probability that a course has both of these things.
By the same logic, we have that:
(a) Find the probability that a course has a final exam or a research paper.
This is
Suppose that 26% of courses have a research paper and a final exam.
This means that
43% of courses require research papers.
So
71% of courses have final exams
So
The probability is
There is an 88% probability that a course has a final exam or a research paper.