Answer: 1 inch
Volume of the cylinder = πr²h
Volume of the cone = 1/3πr²h
If the radius are the same for both the cone and the cylinder, then the liquid will reach 1/3 of its height in the cylinder compared to the cone.
Height = 1/3 x 3 inches
Height = 1 inch
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Answer: The height of the cylinder will be 1 inch.
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The answer is C. Explanation: The line isn’t a straight line, so it can’t be a linear line. Then, do the vertical line test to see if the line is a function (to do this, draw a vertical line through the graph, and see if it passes more than one point on the graph. If the vertical line passes any more than one point on the graph on any spot, it is not a function), and since the graph fails the vertical line test, it is not a function. Therefore, the answer is C.
Answer:
circle area = 1963.495 ft²
Step-by-step explanation:
<u>Given</u>
A rectangle 550 ft by 350 ft packed with circles on a rectangular grid
<u>Find</u>
the area of the largest circle that can be packed this way
<u>Solution</u>
The diameter of the circle must be a factor of both 350 and 550. We want the diameter to be the largest such factor. We can write the factors of 350 and 550 as ...
- 350 = 50 × 7
- 550 = 50 × 11
The largest factor common to both numbers is 50, so that will be the diameter of the largest circle that will fit on a square grid.
The area of a circle is commonly given by the formula ...
A = πr² . . . . . where r represents the radius of the circle.
The radius is half the diameter, so will be (50 ft)/2 = 25 ft. And the area of the circle is ...
A = π(25 ft)² = 625π ft² ≈ 1963.495 ft²
The area of one circle is about 1963.495 square feet.
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The total number of circles is 11×7 = 77. Their total area is 77×1963.495 ft² ≈ 151,189 ft². This is 151,189/192,400 ≈ 78.54% of the total area of the rectangle.
