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Masja [62]
3 years ago
13

!!!! I NEED HELP RIGHT NOW ITS DUE IM 5 MINUTES !!!!

Mathematics
1 answer:
kiruha [24]3 years ago
3 0

Answer:

Step-by-step explanation:

A = h(a+b)/2 for h

2A = h(a + b)

h(a+b) = 2A

h = 2A/(a+b)

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Write an equation for each translation of y=|x| .
aivan3 [116]

Answer:

y = |x| + 7

Step-by-step explanation:

Use desmos.com to see it in action

3 0
4 years ago
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HELP! WILL GIVE BRAINLIEST! DO NOT TAKE ANSWERS OFF ONLINE, THEY ARE WRONG!!!! The following is an incomplete paragraph proving
ohaa [14]

Answer:

The correct option is B.

Step-by-step explanation:

Given information: AB\parallel DCAB∥DC and BC\parallel ADBC∥AD .

Draw a diagonal AC.

In triangle BCA and DAC,

AC\cong ACAC≅AC (Reflexive Property of Equality)

\angle BAC\cong \angle DCA∠BAC≅∠DCA ( Alternate Interior Angles Theorem)

\angle BCA\cong \angle DAC∠BCA≅∠DAC ( Alternate Interior Angles Theorem)

The ASA (Angle-Side-Angle) postulate states that two triangles are congruent if two corresponding angles and the included side of are congruent.

By ASA postulate,

\triangle BCA\cong \triangle DAC△BCA≅△DAC

Therefore option B is correct

4 0
3 years ago
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chubhunter [2.5K]
6/20 chance or simplified would be 3/10. Answer [D] is correct.
5 0
3 years ago
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The Hiking Club plans to go camping in a State park where the
ozzi

Answer: Probability is 0.00205 = 0.205%

Step-by-step explanation: P(rain) = 0.71, P(no rain) = 0.29.

P(no rain in 5 days)= 0.29·0.29·0.29·0.29·0.29= 0.00205

5 0
3 years ago
A basketball player that shoots 80% from the free throw line attempts two free throws. The notation for conditional probability
taurus [48]

Answer:

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)

Step-by-step explanation:

Here given that a basketball player that shoots 80% from the free throw line attempts two free throws.

If x is the no of shoots he makes (say) then we find that each throw is independent of the other.

In other words, because he made successful first attempt, his chances for second attempt will not change

Prob for success in each attempt remains the same as 0.80

Hence I throw is independent of II throw.

When A and B are independent,then we have

P(A/B) = P(A)

Hence answer is

P(made 2nd attempt|made 1st attempt)=P(made 2nd attempt)


8 0
3 years ago
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