If tyler does not eat a diet that includes essential amino acids,his cells will not be able to build what ?

Prescribe how mountains change in abiotic conditions with an increase in elevations

olga55 [171]

The first famous natural scientist to determine how plants change with altitude on tall mountains was Alexander Von Humboldt and Aime Bonpland when climbing some very high volcanoes in South America like Chimborazo at well ove 20,000 feet high and they observed that different plants grow at different altitudes as altitude increases so that as the mountain was ascended the new environments of temperature, moisture,etc would become abiotic for the lower plants but acceptable for the higher elevation plants. In these cases in South America, the lower elevations had very warm temperatures and high humidity so would grow tropical plants with probably large leaves like palm trees etc. On the other hand at high elevations the temperature would be significantly decreased and probably humidity decreased too so only rugged plants like say lichens could grow. At intermediate elevations, most likely say pine trees could grow as I know they do at moderate elevations in Honduras for example.

5 0

4 years ago

In Drosophila, the genes for withered wings (whd), smooth abdomen (sm) and speck body (sp) are located on chromosome 2 and are s

lesya692 [45]

Answer:

A) 47; B) 33; C) 272; D) 122

Explanation:

The three genes are linked.

The female with withered wings and a smooth abdomen has the genotype whd sm sp+/whd sm sp+.

The male with a speck body has the genotype whd+ sm+ sp/whd+ sm+ sp.

Both individuals are homozygous for all genes, so each of them only produces one type of gamete. The resulting F1 therefore has the genotype whd sm sp+/ whd+ sm+ sp, heterozygous for all genes and with a wild-type phenotype.

The females of the F1 were mated with homozygous recessive males (test cross): whd sm sp/whd sm sp.

If we assume interference is 0, the probability of crossing over happening between the genes whd and sm is independent from the probability of crossing over happening between sm and sp.

The distance = frequency of recombination × 100, so the frequency of recombination (RF) between genes whd and sm is 0.305 and the RF between genes sm and sp is 0.155.

<u>The expected double crossover progeny among the 1000 offspring will be:</u>

RF whd-sm × RF sm-sp × 1000 =

0.305 × 0.155 × 1000 = 47 individuals will be double crossover.

Interference is 0.3

The interference is calculated as 1- coefficient of coincidence (cc).

cc = observed double crossover/expected double crossover

Therefore:

I = 1 - cc

cc = 1 - I

Observed DCO / 47 = 0.7

Observed DCO = 0.7 × 47

Observed DCO ≅ 33

The parental gametes are whd sm sp+ and whd+ sm+ sp (the genotype of the F1 female is known).

Looking at them and at the gene map we can tell that the gametes that give rise to withered wings, speck body (whd sm+ sp) and smooth abdomen (whd+ sm sp+) phenotypes are the result of recombination occurring between genes whd and sm.

To calculate the expected number of individuals with those phenotypes among the 1000 progeny we need to determine the frequency of recombination between the genes whd and sm considering there's interference.

The distance whd-sm = RF x 100

The recombination frequency is the sum of the single crossover between whd and sm and the double crossovers.

The frequency of DCO is 33/1000=0.033.

Distance whd-sm/ 100 = SCOwhd-sm + DCO

0.305 - 0.033 = SCO whd-sm

<u>Frequency of SCO whd-sm= 0.272</u>

And the expected number of individuals with those phenotypes will be 0.272 x 1000 = 272.

The gametes that originate the phenotypes withered wings, speck body, smooth abdomen (whd sm sp) and wild type (whd+ sm+ sp+) are the result of recombination between genes sm and sp.

Distance sm-sp/ 100 = SCOsm-sp + DCO

0.155 - 0.033 = SCOsm-sp

<u>Frequency of SCO sm-sp= 0.122</u>

And the expected number of individuals with those phenotypes will be 0.122 x 1000 = 122.

6 0

4 years ago

Explain the analogy that was used to explain DNA Mulations? Idk

Lera25 [3.4K]

Answer:

Explanation:

An example of this analogy might be that the surrounding the central dogma which is compared to making yout mum's recipe for brownies.

First, you ought to call your mum, she stands for the DNA. Then, you pay attention in listening and copying down her instructions. This is can be compared to transcription because during transcription, DNA is copied to mRNA.

Any mistake you do during listening and copying leads to mutation caused by insertion or omission.

4 0

3 years ago

The S phase in the cell cycle is the

BARSIC [14]

It is the part of the cell cycle in which the dna is replicated! vote me brainliest please :) ❤️

4 0

3 years ago

A scientist was observing a population of sea cucumbers in coastal waters. Over a 10-day period, she collected the following inf

Rus_ich [418]

The abiotic factors that could cause the sea cucumbers to differ their distance from one another are temperature, time of the day, and humidity. The biotic factors that could influence are the organisms around these creatures. Furthermore, the independent variable in this study is the time of the day where observed are the average distance between these sea creatures and their output, the distribution of sea cucumbers as the dependent variable.

Hypothesis: There is a link between the time of the day and the distance of sea cucumbers amongst each other.

6 0

3 years ago