Answer:
9514 1404 393
see attached
Step-by-step explanation:
Reflection over the line x = -1 alters the x-coordinates, but leaves the y-coordinates alone. The image point is as far horizontally from the reflection line as the pre-image point is. Each new x-coordinate is the old one subtracted from twice the x-value of the line of reflection: (x, y) ⇒ (-2-x, y) U(-8, -6) ⇒ U'(6, -6) V(-3, -6) ⇒ V'(1, -6) W(-4, -1) ⇒ W'(2, -1)
She should choose data 1! I can’t see the graph
The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Answer:
x=-5, y=-1
Step-by-step explanation:
Substitute x=-4+y into -2x-5y=15. So we have
-2(-4+y)-5y=15
8-2y-5y=15
-7y=7
y=-1
And x is -4+y so x= -4+(-1)= -5.
