Which three lengths could be the lengths of the sides of a triangle?

1 answer:

7 0

9, 14, and 22.
The formula for checking if a triangle will work is side a + side b > side c.
The only one that works is 9, 14, and 22.

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Divide polynomials<br> x2+10x+25/x+5

zhenek [66]

Answer:

x+5

Step-by-step explanation:

Simply it so it is

(x+5)(x+5)/(x+5)

And then you will take out the (x+5) from the numerator and denominator to get the answer.

4 0

2 years ago

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Farmer tom has chickens and sheep he counts 48 heads and 134 legs how many sheep does he have

just olya [345]

Because each chicken has 2 legs you divide 134 by 2 which is 67 then 24 which basically means he has 36 sheep in total. Hope this helped

4 0

2 years ago

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Maurinko [17]

The cross product of two vectors gives a third vector $\mathbf v$ that is orthogonal to the first two.

$\mathbf v=(\vec i+\vec j+\vec k)\times(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\\1&1&1\\4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k$

Normalize this vector by dividing it by its norm:

$\dfrac{\mathbf v}{\|\mathbf v\|}=\dfrac{\vec i+3\,\vec j-4\,\vec k}{\sqrt{1^2+3^2+(-4)^2}}=\dfrac1{\sqrt{26}}(\vec i+3\,\vec j-4\vec k)$

To get another vector orthogonal to the first two, you can just change the sign and use $-\mathbf v$ .