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s344n2d4d5 [400]
4 years ago
13

how long is the arc intersected by a central angle of π/3 radians in a circle with a radius of 6 feet round your answer to the n

earest tenth
Mathematics
2 answers:
riadik2000 [5.3K]4 years ago
4 0

\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ \cline{1-1} r=6\\ \theta =\frac{\pi }{3} \end{cases}\implies s=6\left( \frac{\pi }{3} \right)\implies s=2\pi \implies \stackrel{\textit{rounded up}}{s=6.3}

nata0808 [166]4 years ago
4 0

Answer: arc\ length=6.3\ ft

Step-by-step explanation:

You  need to use the following formula for calculate the arc lenght:

arc\ length=r\theta

Where  "r" is the radius and \theta is the central angle in radians.

You know that the central angle in radians s:

\theta=\frac{\pi }{3}

And the radius is:

r=6\ ft

Therefore, the final step is to substitute the values into the formula. Then you get:

arc\ length=(6\ ft)(\frac{\pi }{3})

arc\ length=6.3\ ft

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