<span>The <u>correct answers</u> are:
x=-3 and x=-8.
Explanation<span>:
We can first write this in standard form, ax</span></span>²<span><span>+bx+c=0. To do this, we will add 11x to both sides:
x</span></span>²<span><span>+24+11x=-11x+11x
x</span></span>²<span><span>+11x+24=0.
Now we can factor this. Look for factors of c, 24, that sum to b, 11. Factors of 24 are:
1 and 24 (sum 25)
2 and 12 (sum 14)
3 and 8 (sum 11)
4 and 6 (sum 10).
The factors we need are 3 and 8, since they sum to 11. This gives us factored form:
(x+3)(x+8)=0.
Using the zero product property, we know that in order to have a product of 0, one or both of the factors must be 0. This means we have:
x+3=0 or x+8=0.
Solving the first equation:
x+3-3=0-3
x=-3.
Solving the second equation:
x+8-8=0-8
x=-8.</span></span>
There are 22 lines the same amount of sides
I think it's -2i+3
I hope this helps!
350÷10=35
350÷15=23 1/3 or 23.34
350÷20=17.50
350÷35=10
a)
And replacing we got:
And simplifying we got:
b) For this case since the coeficient for the higher degree is 2 then the polynomial is of second degree.
c) We need to remember that the closed property for polynomials tell to us that if we apply any operation between two polynomials we need to obtain and other polynomial. For this special case the property is the sum and after multiply we have another polynomial with a higher degree and then the closed property is satisfied.
Step-by-step explanation:
We know a rectangle has sides measuring (4x + 5) units and (3x + 10) units
Part a
For this case we can find the area like this:
And replacing we got:
And simplifying we got:
Part b
For this case since the coeficient for the higher degree is 2 then the polynomial is of second degree.
Part c
We need to remember that the closed property for polynomials tell to us that if we apply any operation between two polynomials we need to obtain and other polynomial. For this special case the property is the sum and after multiply we have another polynomial with a higher degree and then the closed property is satisfied.
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