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Tems11 [23]
2 years ago
9

What is the result of adding -2.9a + 6.8 and 4.4a - 7.37?

Mathematics
2 answers:
riadik2000 [5.3K]2 years ago
8 0
Hey there :)

Adding - 2.9a + 6.8 and 4.4a - 7.37 

- 2.9a + 6.8 + ( 4.4a - 7.37 )

Combine the like terms
- 2.9 + 4.4a + 6.8 - 7.37

1.5a - 0.57 → Your answer
koban [17]2 years ago
7 0
<span> (-2.9a + 6.8 ) +  (4.4a - 7.37)

=</span> -2.9a + 6.8  +  4.4a - 7.37 

= - 2.9a + 4.4a + 6.8 - 7.37

= 1.5a -0.57

Answer: 1.5a - 0.57
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(csc x - 1) (csc x + 1)
victus00 [196]
<h2>Explanation:</h2>

Here we have the following expression:

(csc x - 1) (csc x + 1)

So we need to extend this. Remember that the difference of squares tells us:

(a-b)(a+b)=a^2-b^2

So here:

a=cscx \\ \\ b=1

Thus:

(csc x - 1) (csc x + 1)=csc^2x-1 \\ \\ \\ But: \\ \\ cscx=\frac{1}{sinx} \\ \\ \\ Then: \\ \\ csc^2x-1=\frac{1}{sin^2x}-1=\frac{1-sin^2x}{sin^2x}=\frac{cos^2x}{sin^2x}=cot^2x \\ \\ \\ Finally: \\ \\ \boxed{(csc x - 1) (csc x + 1)=cot^2x}

4 0
3 years ago
The atmospheric pressure on an object decreases as altitude increases. If a is the height (in km) above sea level, then the pres
seraphim [82]

Answer:

373.8mmHg

Step-by-step explanation:

a =height (in km) above sea level,

the pressure P(a) (in mmHg) is approximated given as

P(a) = 760e–0.13a .

To determine the atmospheric pressure at 5.458 km, then we will input into the equation

P(5.458km) = 760e–0.13a .

= 760e^(-0.13×5.458)

=760e^-(0.70954)

= 760×0.4919

=373.8mmHg

Therefore, the atmospheric pressure at 5.458 km is 373.8mmHg

3 0
2 years ago
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