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vladimir2022 [97]
3 years ago
12

A rectangular deck is 9 meters long by 7 meters wide. What is the length someone would walk

Mathematics
1 answer:
Feliz [49]3 years ago
4 0

Answer:

11.4 metres

Step-by-step explanation:

Use Pythagoras theorem for a right-angled triangle

a^2 + b^2 = c^2

if you cut the rectangle in half, it will become a right angled triangle.

a and b are two sides of the rectangle, while c is the diagonal or hypothenuse

so 9^2 + 7^2 = c^2

81 + 49  = c^2

c^ 2 = 130

square root 130 = c

you should get approximately 11.4 metres

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If only you'll clear this up, I'd be happy to help.

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3 0
3 years ago
An ordinary Fair die is a cube with the numbers 1 through 6 on the sides represented by painted spots imagine that such a die is
Hoochie [10]

Answer:  Probability of,  Event A = 5/18

Event B = 1/2

Step-by-step explanation:

Since, The probability of an event = Number of outcomes of the event/ total number of outcomes.

Since, If a fair dire rolled two times then the total number of outcomes, n(S) = 6 × 6 = 36

And, Event A: The sum is greater than 8.

So, possible outcomes are, ( 3,6), (4,5), (4,6), (5,5), (5,6), (5,4), (6,6), (6,5), (6,4), (6,3)

Thus, n(A) = 10

Since, Probability of event A,

P(A) = n(A)/n(S) = 10/36 = 5/18

Therefore, P(A)= 5/18

Now, Event B: The sum is an even number.

So, possible outcomes are, (1,1),(1,3), (1,5), (2,2), (2,4), (2,6), (3,1), (3,3), (3,5), (4,6), (4,2), (4,4), (5,1), (5,3), (5,5), (6,2), (6,4), (6,6)

Thus, n(B)= 18

Since, Probability of event B,

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7 0
2 years ago
if the volume of a cube of wood is 15.625 cm^3 and its mass is 10.00 grams show the calculation for the density of the cube
oee [108]
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7 0
3 years ago
Does anyone know how to work this.
Shtirlitz [24]
I think it's C.

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3 0
3 years ago
Read 2 more answers
What is the midpoint of the vertical line segment graphed below? (2, 4), (2, -9) A. (4, -5). B. (2, -5/2). C. (2, -5). D. (4, 5/
omeli [17]

Answer:

B. (2, -\frac{5}{2})

Step-by-step explanation:

Given:

(2, 4) and (2, -9)

Required:

Midpoint of the vertical line with the above endpoints

Solution:

Apply the midpoint formula, which is:

M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2})

Where,

(2, 4) = (x_1, y_1)

(2, -9) = (x_2, y_2)

Plug in the values into the equation:

M(\frac{2 + 2}{2}, \frac{4 + (-9)}{2})

M(\frac{4}{2}, \frac{-5}{2})

M(2, -\frac{5}{2})

8 0
2 years ago
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