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1 answer:
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Answer: 225
<u>Step-by-step explanation:</u>
n₁ = 2(1) - 1
= 2 - 1
= 1
n₁₅ = 2(15) - 1
= 30 - 1
= 29
= 15 * 15
= 225
Answer:
Area = 32/3
Step-by-step explanation:
x = u ²
y = uv
z = 12v ²
0 ≤ u ≤ 2
0 ≤ v ≤ 1
Since ru = <2u, v, 0> and rv = <0, u, 24v>, we have
Where ru is the differentiation of x, y, z with respect to u and rv is the differentiation of x, y, z wit respect to v.
we find the cross product of ru and rv
ru × rv = 24v²i - 48uv²j + 2u²k
absolute value of ru × rv = 2u² + 24v²
We can now find the area
∫₀² du ∫₀¹ dv (2u² + 24v²) = ∫₀² du [2u²v + 8v³]₀¹ = 32/3
Detailed description can be found in the attachment
The product if a-3 and -2a^2+15a+6b^2 is:
Step-by-step explanation:
In order to find the product of 2 expressions, distributive property can be used.
Given expressions are:
Product of given expressions
Combining like terms
Hence,
The product if a-3 and -2a^2+15a+6b^2 is:
Keywords: Expressions, product
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