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denis23 [38]
3 years ago
11

Please help with this question

Mathematics
1 answer:
Alinara [238K]3 years ago
7 0
The smaller carton would hold 2 3/4
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(5, 3) is the solution to the system of linear equations:<br><br> True<br> False
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I believe it’s true!
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If the arc length of a sector in the unit circle is 4.2, what is the measure of the angle of the sector
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S = rθ
4.2 = 1*θ

The central angle (θ) is 4.2 radians.
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What is the range of the function f(x) = -|X - 4| + 5?
Law Incorporation [45]

Answer:

Range = (-<em>∞, 5</em>)

Step-by-step explanation:

This is the absolute value function with transformation.

The parent function is f(x) = |x|

This function has a "negative" in front, so it makes it reflect about x axis

The -4 after x makes horizontal translation of 4 units right

the +5 at the end makes the function translate 5 units UP

<em>The graph is shown in the attached picture.</em>

<em>Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the </em><em>range is  -infinity to 5</em>

<em />

<em>answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5</em>

3 0
3 years ago
In the figure below, AB=AE, AC=AD and AP is perpendicular to BE. Prove that BC=DE.
NISA [10]

Step-by-step explanation:

1) In the figure, as AB is equal to AE, ABE is an equilateral triangle.

As AP is perpendicular to BE

=> AP is the height of the triangle ABE.

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle.

=> P is the midpoint of BE

=> PE = PB

2) In the figure, as AC = AD, so that ACD is an equilateral triangle.

As AP is perpendicular to BE,  so that it is perpendicular to CD as well

=> AP is the height of the triangle ACD

In an equilateral triangle, the median and the height is the same, so that AP is also the median of the triangle ACD.

=> P is the midpoint of CD

=> PC = PD

We have:

+) PB = PE

+) PC = PD

=> PB - PC = PE - PD => BC = DE

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3 years ago
Mhanifa please help! Look at the picture attached!!!
inessss [21]

Answer:

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Sum of interior angles of a quadrilateral is 360°

  • 110° + 130° + x + x - 3° = 360°
  • 2x = 360° - 237°
  • 2x = 123°
  • x = 61.5°

(18)

Sum of interior angles of a hexagon is 180°*(6 - 2) = 720°

  • 2*90° + 2x + 2(x + 22°) = 720°
  • 90° + x + x + 22° = 360°
  • 2x = 360° - 112°
  • 2x = 248°
  • x = 124°

(19)

Interior angles of a given pentagon are all marked as congruent, so the exterior angles are congruent too.

Sum of exterior angles is 360°.

  • x = 360°/5
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3 years ago
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