Answer:
m₁×m₂ = -1
m₁ = 3 and m₂ = -1/3
3×-1/3 = -1
-1 = -1
Hence proved, the given two lines are perpendicular.
Step-by-step explanation:
You can prove that the two lines are perpendicular if the following condition holds true.
m₁×m₂ = -1
Where m₁ is the slope of line 1 and m₂ is slope of line 2
So first you have to find out the slope of each line.
You are given 2 equations
y = 3x + 5 eq. 1
6y + 2x = 1 eq. 2
You have to write these equations in slope-intercept form to find out their slopes.
The slope-intercept form is given by
y = mx + b
Comparing the general form with eq. 1
y = 3x + 5
We notice that the slope is m₁ = 3
Now convert the eq. 2 into slope-intercept form
6y + 2x = 1 eq. 2
6y = -2x + 1
y = (-2x + 1)/6
y = -1/3x + 1/6 eq. 2
Comparing the general form with eq. 2
y = -1/3x + 1/6
We notice that the slope is m₂ = -1/3
Now we have slopes of both lines so let us test whether they are perpendicular or not
m₁×m₂ = -1
m₁ = 3 and m₂ = -1/3
3×-1/3 = -1
-1 = -1
Hence proved, the given two lines are perpendicular.
Answer:
Step-by-step explanation:
2(x+y)=parameter
xy=area
If area=parameter then 2(x+y)=xy.
If y=3, then
2(x+3)=3x
2x+6=3x
X=6
now, let’s double check.
6*3=18
2(3+6)=18
Answer:
6 you would calculate it just like vertical length
<span>-(9x + 8) - 2(x -5)
= </span><span>-9x - 8 - 2x + 10
= -11x + 2</span>
Answer:
it would be 20 miles per hour
