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3 years ago

Which value of x makes the following equation true?

Mathematics

2 answers:

goldfiish [28.3K]3 years ago

8 0

3x-6=-3x+30
3x+3x=30+6
6x=36
x=6

Eddi Din [679]3 years ago

3 0

$3(x-2)= -3 x+30\\
3x-6=-3x+30\\
6x=36\\
x=6$

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25-3=22

22/2 = 11

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3 years ago

A Florida newspaper reported on the topics that teenagers most want to discuss with their parents. The findings, the results of

ANEK [815]

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Step-by-step explanation:

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2 years ago

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Answer:

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Read 2 more answers

The height of a ball thrown into the air after t seconds have elapsed is h = −16t2 + 40t + 6 feet. What is the first time, t, wh

sp2606 [1]

<h3>The first time when the ball will reach a height of 20 feet is 0.42 seconds</h3>

Solution:

Given that,

The height of a ball thrown into the air after t seconds have elapsed is:

$h = -16t^2 + 40t + 6$

What is the first time, t, when the ball will reach a height of 20 feet?

Substitute h = 20

$20 = -16t^2 + 40t + 6\\\\-16t^2 + 40t + 6 -20 = 0\\\\-16t^2 + 40t -14 = 0\\\\16t^2 -40t + 14 = 0\\\\8t^2 -20t + 7=0$

Solve by quadractic formula

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$\mathrm{For\:}\quad a=8,\:b=-20,\:c=7$

$t = \frac{-\left(-20\right)\pm \sqrt{\left(-20\right)^2-4\cdot \:8\cdot \:7}}{2\cdot \:8}\\\\t = \frac{20 \pm \sqrt{176}}{16}\\\\t = \frac{20 \pm 4\sqrt{11}}{16}\\\\t = \frac{ 5 \pm \sqrt{11}}{4}\\\\We\ have\ two\ solutions\\\\ t=2.07915, \:t=0.42084$

Rounding off we get,

t = 2.08 , t = 0.42

Thus the first time when the ball will reach a height of 20 feet is 0.42 seconds

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3 years ago

Test

ziro4ka [17]

Answer:

36m/3

Step-by-step explanation:

because I took the test and all ready know that answer

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1 year ago