Answer:
53/100?
Step-by-step explanation:
I mean you can't really simplify it any more. There's no LCD, GCD. Can't divide it evenly.
To solve it I just looked at the number of places, (3 which mean 100.)
Then I looked at the numbers, (53.)
So you just turn that into a fraction...
7/8 and 3/4
Both need to have same denominator so it would be 32, in this case because 8*4 is 32.
7/32+3/32=10/32 simplified to 5/16
Answer:
Mai
Step-by-step explanation:
To find the rate, you must determine who is going faster per minute. To do this, you must divide the total number of miles by the total number of minutes.
Mai: 5 miles / 15 minutes = 1/3 miles per minute
Jada: 4 miles / 14 minutes = 2/7 miles per minute
Then, use a common denominator to make calculations easier:
Mai: 1/3 * 7/7
Jada: 2/7 * 3/3
You should get:
Mai: 7/21 miles per minute
Jada: 6/21 miles per minute
By looking at this, you can see that Mai is traveling slightly faster, going more miles than Jada per minute.
9x^3-39x^2-38x+40=(3x-2)(3x+4)(x-5) by synthetic division
Thus roots are -4/3, 2/3, 5
<span>(a) At the end of Month 0, about how many more insects were in Pod A than Pod B? Explain.
In Pod A, the point is higher than 50, it could be 60 to 70 insects. Pod B has 20 insects. So, Pod A has at least 40 insects more than Pod B.
(b) Find and compare the growth rates of each pod. Show your work.
Pod A: (0,60) ; (1,80) ; (2,100)
(80-60)/60 = 0.33
(100-80)/80 = 0.25
Pod B: (0,20) ; (1,44) ; (2,97)
(44-20)/20 = 1.2
(97-44)/44 = 1.2
Based on my computation, the rate of Pod A is lower than the rate of Pod B.
(c) When does the population in Pod B exceed the population in Pod A? Explain.
Pob B exceeds the population of Pod A at the END OF MONTH 4.
Pod A has a population of less than 200 while Pod B has a population of 469.</span>
