Given the dimensions of locker box are length = 6 feet, width = 4 feet, and height = 10 feet.
Wayne wants to cover the box, so we need to find its total surface area. The box is in the shape of rectangular prism.
We know the formula for total surface area of rectangular prism is given as follows :-
T.S.A. = 2·(6 x 4 + 4 x 10 + 10 x 6) = 2·(24 + 40 + 60) = 2·(124) = 248 feet²
Surface Area = 248 squared feet
To cover the locker with waterproof covering, we needed to find the surface area of the box. As we multiplied two dimensions at a time in the formula, so the units are "squared feet".
Hence, option A is correct i.e. squared feet or ft².
So 1st consider that it's a square! That's very important. So for a square, all 4 sides are equal.
And now considering that the given information is the diameter. So any angle made at the circle extended from the 2 points of diameter gives an angle of 90°
Now consider one triangle. So we already know that 2 sides of the triangle are equal (because they are 2 sides of a square) , has a side of 10 (diameter) and and angle of 90°. So remaining 2 angles are 45°
Now solve it by applying
Answer:
A function can have many x values for a given y value and still be a function but it cannot have many y values for a given x value. You can easily test this by graphing the equation and doing the vertical line test by seeing if a vertical line will intersect the graph only once at all x values, if it passes it is a function. In short what you have here is a function
Step-by-step explanation:
I think there is no simplified fractions for this number it will be the same -4/17
Answer:
No solutions
Explanation:
The given system of equations is
2y = x + 9
3x - 6y = -15
To solve the system, we first need to solve the first equation for x, so
2y = x + 9
2y - 9 = x + 9 - 9
2y - 9 = x
Then, replace x = 2y - 9 on the second equation
3x - 6y = -15
3(2y - 9) - 6y = -15
3(2y) + 3(-9) - 6y = -15
6y - 27 - 6y = -15
-27 = -15
Since -27 is not equal to -15, we get that this system of equation doesn't have solutions.
