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3 years ago

Solve using the Quadratic Formula: 3x2 + 3x - 6 - 0 -2, 1 1, 2 -3, 9 -3, -9

1 answer:

6 0

Assuming that the equation is 3x^2+3x-6=0, then use the quadratic equation, (-b+- sqrt(b^2-4ac))/2a, with ax^2+bx+c as the original equation. so here we get (-3+-sqrt(9+72))/6 = (-3+-sqrt(81))/6 = (-3+-9)/6, = (-1+-3)/2 = 1 or -2. Plug in original to check.

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Olegator [25]

mhorn seems to be correct

Step-by-step explanation:

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2 years ago

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An individual who has automobile insurance from a certain company is randomly selected. Let Y be the number of mov- ing violatio

olga2289 [7]

Answer:

a) $E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

b) $E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

Step-by-step explanation:

We assume the following distribution given:

Y 0 1 2 3

P(Y) 0.60 0.25 0.10 0.05

Part a

We can find the expected value with this formula:

$E(Y) = \sum_{i=1}^n Y_i P(Y_i)$

And replacing we got:

$E(Y) =0*0.60 +1*0.25 +2*0.1 +3*0.05 = 0.60$

Part b

If we want to find the expected value of $100 Y^2$ we need to find the expected value of Y^2 and we have:

$E(Y^2) = \sum_{i=1}^n Y^2_i P(Y_i)$

And replacing we got:

$E(Y^2) =0^2*0.60 +1^2*0.25 +2^2*0.1 +3^2*0.05 = 1.1$

And then the expected value would be:

$E(100Y^2) = 100*1.1= 110$

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3 years ago

I NEED HELP PLEASE ...ASAP!!!!!

attashe74 [19]

-a²-3b³+c²+2b³-c²

= -(3)² - (3×2)³ + (-3)² + (2 × 2)³ - ( -3)²

= 9 - 24 + 9 + 16 - 9

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answer is 1.

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