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3 years ago

10

Solve using the Quadratic Formula: 3x2 + 3x - 6 - 0 -2, 1 1, 2 -3, 9 -3, -9

1 answer:

AysviL [449]3 years ago

6 0

Assuming that the equation is 3x^2+3x-6=0, then use the quadratic equation, (-b+- sqrt(b^2-4ac))/2a, with ax^2+bx+c as the original equation. so here we get (-3+-sqrt(9+72))/6 = (-3+-sqrt(81))/6 = (-3+-9)/6, = (-1+-3)/2 = 1 or -2. Plug in original to check.

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Which values of a and b make the following equation true? a = 11, b = 7 a = 11, b = 10 a = 28, b = 7 a = 28, b = 10

xz_007 [3.2K]

Answer:

The answer is

<h2>a = 11, b = 7</h2>

Step-by-step explanation:

$( {5x}^{7} {y}^{2} )( { - 4x}^{4} {y}^{5} ) = - 20 {x}^{a} {y}^{b}$

Multiply the terms on the left side of the equation

That's

$- 20 {x}^{11} {y}^{7} = - 20 {x}^{a} {y}^{b}$

Since the bases are the same we can equate the exponents

That's

${x}^{11} = {x}^{a}$

a = 11

And

${y}^{7} = {y}^{b}$

b = 11

Therefore

a = 11 and b = 7

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Answer:

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