Solve using the Quadratic Formula: 3x2 + 3x - 6 - 0 -2, 1 1, 2 -3, 9 -3, -9

1 answer:

6 0

Assuming that the equation is 3x^2+3x-6=0, then use the quadratic equation, (-b+- sqrt(b^2-4ac))/2a, with ax^2+bx+c as the original equation. so here we get (-3+-sqrt(9+72))/6 = (-3+-sqrt(81))/6 = (-3+-9)/6, = (-1+-3)/2 = 1 or -2. Plug in original to check.

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