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skad [1K]
4 years ago
12

Does this look right?

Mathematics
1 answer:
chubhunter [2.5K]4 years ago
7 0
Yes. it looks right to me
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Two mechanics worked on a car. The first mechanic to work for 5 Hours in the second mechanic work for 15 Hours. Together they ch
Butoxors [25]
<h2>Hello!</h2>

The answers is:

The first mechanic's rate is $70 per hour.

The second mechanic's rate is $110 per hour.

<h2>Why?</h2>

Let's write the given information in order to make the equations that will help us to solve this problem.

Let be "x" the first mechanic's rate and "y" the second mechanic's rate, so:

If the first mechanic worked for 5 hours and the second mechanic worked for 15 hours, and the together charged a total of $2000.

5x+15y=2000

Also, we know that the sum of the two rates was $170 per hour, so:

x+y=180

Then, isolating "x" and replacing it into the first equation, we have:

x=180-y

5(180-y)+15y=2000

900-5y+15y=2000

10y=2000-900

10y=1100

y=\frac{1100}{10}=110

So, the second mechanic's rate is $110 per hour.

Now, to calculate the first mechanic's rate we need to replace "y" into the second equation:

x+y=180\\x+110=180\\x=180-110=70

So, the first mechanic's rate is $70 per hour.

Have a nice day!

7 0
3 years ago
Help pleaseeeeee thanks so much
aleksklad [387]

Answer:

The answer is n = <u>31</u>

Step-by-step explanation:

Equation:   <u>2n + 13</u> = 75

2n = 75 - 13

2n = 62

n = 62/2

n = 31

check:

2*31 + 13 = 75

62 + 13 = 75

4 0
4 years ago
Read 2 more answers
A class consists of 13 boys and 10 girls. They want to elect officers so that the president and secretary are girls, and the vic
Viktor [21]

Answer:

10 boys and ten girls

Step-by-step explanation:

if there are 13 boys and 10 girls,and 3 boys dont participate,then there are 10 boys. making there an equal ammout of boys and girls.

not sure if this is what you were asking but if it was then i hope it helps

8 0
3 years ago
Find the area of the trapezoid when height = 5in, base1 = 12in, and base2 = 15in.
myrzilka [38]
A= (a+b)/2*h
A=(12+15)/2*5
A=(27/2)*5
A=13.5*5
A=67.5in
5 0
3 years ago
Read 2 more answers
From y² + 5 y - 7, subtract y² - 3 y - 4​
Vaselesa [24]

<h3>{y}^{2}  + 5y - 7 - ( {y}^{2}  - 3y - 4) \\  {y}^{2}  + 5y - 7 -  {y}^{2}  + 3y + 4 \\  {y}^{2}  - y {}^{2}  + 5y + 3y - 7 + 4 \\ 8y - 3</h3>
3 0
3 years ago
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